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antiseptic1488 [7]
3 years ago
11

What happens when an electron emits a photon?

Physics
1 answer:
Vera_Pavlovna [14]3 years ago
7 0

Answer:

An electron emits a photon and falls from a higher energy level to a lower energy level.

Explanation:

A quantized form of electromagnetic radiation is called a photon.

Since the electromagnetic radiation has dual characteristics. The photons are the energy wave packets of the radiation.

When an electron is exposed to such radiation, it absorbs some of the energies of photons and goes to the excited state.

The excited state is only a temporary state. So, the electron releases some energy that comes to a lower energy level.

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A thin aluminum rod lies along the x-axis and has current of I = 16.0 A running through it in the +x-direction. The rod is in th
coldgirl [10]

Answer:

a) The magnitude of the magnetic field = 7.1 mT

b) The direction of the magnetic field is the +z direction.

Explanation:

The force, F on a current carrying wire of current I, and length, L, that passes through a magnetic field B at an angle θ to the flow of current is given by

F = (B)(I)(L) sin θ

F/L = (B)(I) sin θ

For this question,

(F/L) = 0.113 N/m

B = ?

I = 16.0 A

θ = 90°

0.113 = B × 16 × sin 90°

B = 0.113/16 = 0.0071 T = 7.1 mT

b) The direction of the magnetic field will be found using the right hand rule.

The right hand rule uses the first three fingers on the right hand (the thumb, the pointing finger and the middle finger) and it predicts correctly that for current carrying wires, the thumb is in the direction the wire is pushed (direction of the force; -y direction), the pointing finger is in the direction the current is flowing (+x direction), and the middle finger is in the direction of the magnetic field (hence, +z direction).

3 0
3 years ago
A 60 kg box is lifted by a rope a distance of 10 meters straight up at constant speed. how much power is required to complete th
Nadya [2.5K]
Power=Work/Time
The work done is the energy required to lift the box, fighting the force of gravity. So, Work=Potential energy of the box at 10 meters.

W=PE=mgh=(60)(9.8)(10)=5880J
Finally,
P=W/T=(5880)/(5)=1176Watt

So the answer is 1176 Watts
3 0
3 years ago
Read 2 more answers
Bob is moving at 0.967c with respect to Alice. At the exact instant he passes Alice, she fires a very short laser pulse in the s
yulyashka [42]

Explanation:

Speed of Bob, v = 0.967 c

At the exact instant he passes Alice, she fires a very short laser pulse in the same direction Bob is moving.

(a) We need to find the distance measured by Alice  between Bob and the laser pulse. It is given by :

d=ct-vt

d=t(c-v)

d=5.59\times (c-0.967c)

d=5.53\times 10^7\ meters

(b) Distance measured by Bob between himself and the laser pulse is given by :

d_B=ct

d_B=3\times 10^8\times 5.59

d_B=6.67\times 10^9\ meters

Hence, this is the required solution.  

8 0
3 years ago
a 0.0780 kg lemming runs off a 5.36 m high cliff at 4.84 m/s. what is its kinetic energy when it's 2.00 m above the ground
Blababa [14]

Answer:

KE_2 = 3.48J

Explanation:

Conservation of Energy

E_1 = E_2

PE_1+KE_1 = PE_2+KE_2

m*g*h+(1/2)m*v² = m*g*h+(1/2)m*v²

(0.0780kg)*(9.81m/s²)*(5.36m)+(.5)*(0.0780kg)*(4.84m/s)² = (0.0780kg)*(9.81m/s²)*(2m)+KE_2

4.10J+0.914J = 1.53J + KE_2

5.01J = 1.53J + KE_2

KE_2 = 3.48J

3 0
3 years ago
A machine part has the shape of a solid uniform sphere of mass 245 g and diameter 4.30 cm . It is spinning about a frictionless
Alla [95]

Answer:

Angular acceleration, \alpha =9.49\ rad/s^2

Explanation:

It is given that,

Mass of the solid sphere, m = 245 g = 0.245 kg

Diameter of the sphere, d = 4.3 cm = 0.043 m

Radius, r = 0.0215 m

Force acting at a point, F = 0.02 N

Let \alpha is its angular acceleration. The relation between the angular acceleration and the torque is given by :

\tau=I\times \alpha

I is the moment of inertia of the solid sphere

For a solid sphere, I=\dfrac{2}{5}mr^2

\alpha =\dfrac{\tau}{I}

\alpha =\dfrac{F.r}{(2/5)mr^2}

\alpha =\dfrac{5F}{2mr}

\alpha =\dfrac{5\times 0.02}{2\times 0.245\times 0.0215}

\alpha =9.49\ rad/s^2

So, its angular acceleration is 9.49\ rad/s^2. Hence, this is the required solution.

3 0
3 years ago
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