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Molodets [167]
3 years ago
9

Determine the direction of the force that will act on the charge in each of the following situations. A negative charge moving t

o the left in a magnetic field that points out of the screen. A negative charge moving to the left in an electric field that points out of the screen. A positive charge moving downward in a magnetic field that points upward. Answer Bank
Physics
1 answer:
wlad13 [49]3 years ago
6 0

Answer:

a) DOWN direction,  b)  directed INTO THE SCREEN, c)    F = 0

Explanation:

The direction of the force is

for electric force

           F = q E

where we assume a positive test charge, for which the force has the direction of the electric field.

For a magnetic field

in this case the direction of the force is given by the right hand rule.

For a positive test charge, the thumb points in the direction of velocity, the other fingers extended in the direction of the magnetic field, and the palm gives the direction of force for a positive charge.

           F = q v x B

Let us apply these considerations to our case.

a) negative charge moving to the left

in a magnetic field points away from the screen

In this case the thumb goes to the left, the fingers extended outwards and the palm points upwards, but since the charge is negative the force has a DOWN direction.

b) negative charge moves to the left

in electric field it points off the screen.

The outside is in the direction of the electric field and since the charge is negative, the force is directed INTO THE SCREEN

c) positive charge moves down

in magnetic field points up

in this case the velocity and the field have the same direction so the vector product of them is zero

       F = q v  B sin 0

       F = 0

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The image is missing, so i have attached it.

Answer:

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Explanation:

From the image,

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Expanding, we have;

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From the diagram, x = 80

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dy/dx = -0.5

Also, d²y/dx² = -40/6400

d²y/dx² = -1/160

Now,

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Plugging in the relevant values;

R = [(1 + (-0.5)²)^(3/2)]/(-1/160)

R = -223.61m

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We know that acceleration (a_n) = v²/R

Thus, a_n = 9²/223.61

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a_n = 0.3622 m/s²

Now, to get the resultant normal force. From the diagram, resolving forces, gives;

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We are given; m = 0.8 x 10³ kg

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Thus,tanθ = - 1.5

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θ = 26.6°

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Thus;

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N = (0.8 x 10³ x 9.81 x 0.8942) - (0.8 x 10³ x 0.3622)

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F_f = m(v/t) - Wsin26.6

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F_f = 2400 - 3514.33

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The wavelength of the yellow light from a sodium flame is 589 nm. This light originated from a sodium atom in the hot flame.
DiKsa [7]

From wave speed formula, period is 1.96 × 10^-15  seconds per cycle and the frequency is 5.1 × 10^14 Hertz

<h3>What is Frequency ?</h3>

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Given that the wavelength of the yellow light from a sodium flame is 589 nm. This light originated from a sodium atom in the hot flame.

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