Question

A car accelerates uniformly from rest to 60 km/h in 30 s. What is its displacement during this time?

Answer 1

Answer:

252.62 m

Explanation:

Data provided :

Initial speed of the car, u = 0 Km/h  (since, the car starts from the rest)

Final speed of the car, v = 60 km/h = 60 × (5/18) = 16.67 m/s

Time, t = 30 s

now,

from the Newton's equation of motion, we have

v = u + at

where,

a is the acceleration of the car

on substituting the values, we have

16.67 = 0 + a × 30

or

a = 0.55 m/s²

also,

v² - u² = 2as

where, s is the distance traveled

on substituting the values, we get

16.67² - 0² = 2 × 0.55 × s

or

s = 252.62 m