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BARSIC [14]
3 years ago
7

A car accelerates uniformly from rest to 60 km/h in 30 s. What is its displacement during this time?

Engineering
1 answer:
Rina8888 [55]3 years ago
5 0

Answer:

252.62 m

Explanation:

Data provided :

Initial speed of the car, u = 0 Km/h  (since, the car starts from the rest)

Final speed of the car, v = 60 km/h = 60 × (5/18) = 16.67 m/s

Time, t = 30 s

now,

from the Newton's equation of motion, we have

v = u + at

where,

a is the acceleration of the car

on substituting the values, we have

16.67 = 0 + a × 30

or

a = 0.55 m/s²

also,

v² - u² = 2as

where, s is the distance traveled

on substituting the values, we get

16.67² - 0² = 2 × 0.55 × s

or

s = 252.62 m

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According to fire regulations in a town, the pressure drop in a commercial steel, horizontal pipe must not exceed 2.0 psi per 25
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Answer:

6.37 inch

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\frac{P1}{\rho } + \frac{v_{2} }{2g} +z_{1}  = \frac{P2}{\rho } + \frac{v2^{2} }{2g} + z_{2} + f\frac{l}{D} \frac{v^{2} }{2g}

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Therefore, pressure drop, (P1-P2)/p = 2.70 ft

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Correlating with the chart, we find that the diameter will be D= 0.513

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