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zhuklara [117]
2 years ago
8

a. A crude oil pipe’s radius is reduced by 5%. What is the corresponding percentage change in the pressure drop per unit length?

b. A pipe’s radius can be thought of as a characteristic dimension, D. What is the surface-to-volume ratio (S/V) of the inside of the pipe as a function of D?
Engineering
1 answer:
Lapatulllka [165]2 years ago
6 0

Answer: a) 10% b) 1/D

Explanation:

a)

The change in pressure is inversely proportional to the square of the radius.

Now if radius of pipe originally= 1

So, radius of pipe after reduction= 0.95

Now percentage change in pressure drop per unit length= (\frac{1^{2} }{0.95^{2} }- 1) * 100

Percentage change in pressure= 0.1 or 10%

b)

Surface area in terms of D= D²

Volume in terms of D= D³

Surface area to volume ratio in terms of D= \frac{D^{2} }{D^{3} }

S/V ratio= 1/D

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A water pump delivers 3 hp of shaft power when operating. If the pressure differential between the outlet and the inlet of the p
Natali [406]

Answer:

Mechanical Efficiency =  83.51%

Explanation:

Given Data:

Pressure difference = ΔP=1.2 Psi

Flow rate = V=8ft^3/s\\

Power of Pump = 3 hp

Required:

Mechanical Efficiency

Solution:

We will first bring the change the units of given data into SI units.

P=1.2*6.895 = 8.274KPa\\V=8*0.00283=0.226 m^3/s\\P=3*0.746=2.238KW

Now we will find the change in energy.

Since it is mentioned in the statement that change in elevation (potential energy) and change in velocity (Kinetic Energy) are negligible.

Thus change in energy is

=(Mass * change in P)/density\\= \frac{M*P}{p}\\\\

As we know that Mass = Volume x density

substituting the value

Energy = Volume * density x ΔP / density

Change in energy = Volumetric flow x ΔP

Change in energy = 0.226 x 8.274 = 1.869 KW

Now mechanical efficiency = change in energy / work done by shaft

Efficiency = 1.869 / 2.238

Efficiency = 0.8351 = 83.51%

5 0
3 years ago
What information does the api symbol or donut provide?.
kondor19780726 [428]

Answer:

The API "Donut" identifies oils that meet current API engine oil standards.

Explanation:

hope this helps :)

7 0
2 years ago
S1.1 The Acre-Foot. Hydraulic engineers in the United States often use, as a unit of volume of water, the acre-foot, defined as
Mars2501 [29]

Answer:

1072 acre foot

1331424000 kg

Explanation:

1 feet has 12 inches, so 2 in is 0.167 feet.

1 km^2 has 1 million m^2.

1 acre is 4074 m^2.

So, 1 km is 247 acres.

Then 26 km^2 is 6422 acres.

So, the volume of water is

6422 * 0.167 = 1072 acre-foot

Since one cubic meter of water has 1000 kg

One inch is 25.4 mm = 0.0254 m

One feet is 12 * 0.0254 = 0.3048 m

An acre-feet has a volume of

4074*0.3048 = 1242 m^3

And that is a mass of water of

1242 * 1000 = 1242000 kg/acre-feet

Therefore the mass of rainwater in the town is of

1072 * 1242000 = 1331424000 kg = 1331424 tons

4 0
3 years ago
Carbon dioxide used as a natural refrigerant flows through a cooler at 10 MPa, which is supercritical, so no condensation occurs
kupik [55]

Answer:

The answer which is a calculation can be found as an attached document

Explanation:

5 0
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Explain why it is important to understand hydrostatic forces on surfaces when designing scuba gear, particularly oxygen tanks, f
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Answer:

Explained

Explanation:

Oxygen tank = Oxygen enriched air tank

Hydro static pressure increases with the depth, generally around 1 bar for 10 meters of depth. This high pressure condition leads to increasing in the partial pressure of oxygen in the scuba tank. This leads to a condition called oxygen toxicity. It causes when breathing molecular oxygen at higher partial pressures. It leads to cell damage in the nervous system, lungs, and eyes. So, while designing such gear we have to be careful that oxygen partial pressure shouldn't exceed certain pressure.

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3 years ago
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