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3 years ago

13

What does it take to launch a rocket in space?

2 answers:

il63 [147K]3 years ago

5 0

You need more than enough fuel engine to blast you up in to space for if anything goes wrong you have enough

Dafna11 [192]3 years ago

3 0

To get rockets into orbit, they need much more thrust than the amount that will get them up to the required altitude. They also need sufficient thrust to allow them to travel with very high orbital speed. ... If speed is less than this, an object will fall back to the Earth

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A rigid tank of volume of 0.06 m^3 initially contains a saturated mixture of liquid and vapor of H2O at a pressure of 15 bar and

Serga [27]

Answer:

The total mass in the tank = 0.45524 kg

The amount of heat transferred = 3426.33 kJ

Explanation:

Given that:

The volume of the tank V = 0.06 m³

The pressure of the liquid and the vapor of H2O (p) = 15 bar

The initial quality of the mixture $\mathbf{x_{initial} - 0.20}$

By applying the energy rate balance equation;

$\dfrac{dU}{dt} = Q_{CV} - m_eh_e$

where;

$m_e =- \dfrac{dm_{CV}}{dt}$

Thus, $\dfrac{dU}{dt} =Q_{CV} + \dfrac{dm_{CV}}{dt}h_e$

If we integrate both sides; we have:

$\Delta u_{CV} = Q_{CV} + h _e \int \limits ^2_1 \ dm_{CV}$

$m_2u_2 - m_1 u_1 = Q_{CV} + h_e (M_2-m_1) \ \ \ --- (1)$

We obtain the following data from the saturated water pressure tables, at p = 15 bar.

Since:

$h_e =h_g$

Then: $h_g = h_e = 2792.2 \ kJ/kg$

$v_f = 1.1539 \times 10^{-3} \ m^3 /kg$

$v_g = 0.1318 \ m^3/kg$

Hence;

$v_1 = v_f + x_{initial} ( v_g-v_f)$

$v_1 = 1.1529 \times 10^{-3} + 0.2 ( 0.1318-1.159\times 10^{-3} )$

$v_1 = 0.02728 \ m^3/kg$

Similarly; we obtained the data for $u_f \ \& \ u_g$ from water pressure tables at p = 15 bar

$u_f = 843.16 \ kJ/kg\\\\ u_g = 2594.5 \ kJ/kg$

Hence;

$u_1 = u_f + x_{initial } (u_g -u_f)$

$u_1 =843.16 + 0.2 (2594.5 -843.16)$

$u_1 = 1193.428$

However; the initial mass $m_1$ can be calculated by using the formula:

$m_1 = \dfrac{V}{v_1}$

$m_1 = \dfrac{0.06}{0.02728}$

$m_1 = 2.1994 \ kg$

From the question, given that the final quality; $x_2 = 1$

$v_2 = v_f + x_{final } (v_g - v_f)$

$v_2 = 1.1539 \times 10^{-3} + 1(0.1318 -1.1539 \times 10^{-3})$

$v_2 = 0.1318 \ m^3/kg$

Also;

$u_2 = u_f + x_{final} (u_g - u_f)$

$u_2 = 843.16 + 1 (2594.5 - 843.16)$

$u_2 = 2594.5 \ kJ/kg$

Then the final mass can be calculated by using the formula:

$m_2 = \dfrac{V}{v_2}$

$m_2 = \dfrac{0.06}{0.1318}$

$m_2 = 0.45524 \ kg$

Thus; the total mass in the tank = 0.45524 kg

FInally; from the previous equation (1) above:

$m_2u_2 - m_1 u_1 = Q_{CV} + h_e (M_2-m_1) \ \ \ --- (1)$

$Q = (m_2u_2-m_1u_1) - h_e(m_2-m_1)$

Q = [(0.45524)(2594.5) -(2.1994)(1193.428)-(2792.2)(0.45524-2.1994)]

Q = [ 1181.12018 - 2624.825543 - (2792.2)(-1.74416 )]

Q = 3426.33 kJ

Thus, the amount of heat transferred = 3426.33 kJ

7 0

3 years ago

Which of the following lists, among other things, the vehicle identification, the customer's concern or complaint, and costs for

Free_Kalibri [48]

Answer:

I think it is D.service manual

Explanation:

Because it is the vehicle identification

6 0

2 years ago

Recall a recent decision that you had difficulty making. How did you diagnose and solve the challenge? Were the consequences goo

blsea [12.9K]

Answer:

yes maybe

Explanation:

I have a project and everyone in the world will know about it.

7 0

3 years ago

Explain, using at least three reasons, why Timothy would fail to be a good match as a mechanical engineer in the following scena

mina [271]

Explanation: I'm sorry I can't really give an answer because there isn't really a topic on this question.

3 0

2 years ago

In the circuit below I 1=20mA V1=10 R1=400 R2=2000 R3=1000. Use node analysis to find R2

Hatshy [7]

Answer:0.2A

Explanation:

First, write KCL

i1-i2-i3=0

Then, replace currents with viltages and resistors.

V2-10v/100-v2/200-v2/400=0

V2-40=0

V2=40v

I hope it was helpful

6 0

3 years ago