Lance is the sitting judge in the local family court. What education might have been

Problem Statement: Air flows at a rate of 0.1 kg/s through a device as shown below. The pressure and temperature of the air at l

Tema [17]

Answer:

The answer is "+9.05 kw"

Explanation:

In the given question some information is missing which can be given in the following attachment.

The solution to this question can be defined as follows:

let assume that flow is from 1 to 2 then

Q= 1kw

m=0.1 kg/s

From the steady flow energy equation is:

$m\{n_1+ \frac{v^2_1}{z}+ gz_1 \}+Q= m \{h_2+ \frac{v^2_2}{2}+ gz_2\}+w\\\\\ change \ energy\\\\0.1[1.005 \times 800]-1= 0.01[1.005\times 700]+w\\\\w= +9.05 \ kw\\\\$

If the sign of the work performed is positive, it means the work is done on the surrounding so, that the expected direction of the flow is right.

8 0

3 years ago

Shane's 100-watt radio draws 7 amps of current on a 120-volt circuit. What is the resistance in the radio?

lawyer [7]

Answer:

Resistance, R = 2.04 Ohms.

Explanation:

Given the following data;

Current = 7 amps

Circuit voltage = 120 Volts

Power = 100 Watts

To find the resistance;

First of all, we would calculate the potential difference (voltage level) used by the radio.

Power = current * voltage

100 = 7 * voltage

Voltage = 100/7

Voltage = 14.29 Volts

Next, we solve for the resistance of the radio;

Ohm's law states that at constant temperature, the current flowing in an electrical circuit is directly proportional to the voltage applied across the two points and inversely proportional to the resistance in the electrical circuit.

Mathematically, Ohm's law is given by the formula;

$V = IR$

Where;

V represents voltage measured in voltage.

I represents current measured in amperes.

R represents resistance measured in ohms.

Substituting into the formula, we have;

$14.29 = 7*R$

$R = \frac {14.29}{7}$

Resistance, R = 2.04 Ohms.

7 0

2 years ago

Technician A says that for any fuel to burn efficiently, it must be vaporized and fully mixed with the proper amount of air. Tec

Ira Lisetskai [31]

Both technicians are correct

Explanation:

They are each correct for separate reasons. Tech A is correct due to pressure and temperature both being important factors and quantities to vaporize anything. Tech B is correct due to fuel particles being easier to burn due to their chemical structure.

8 0

1 year ago

Technician A says that diesel fuel system filters also include a water separator. Technician B says that water from the separato

Verizon [17]

Answer:

A is correct

Explanation:

water can cause several types of problems in a high pressure fuel injection system. Within reasonable and fairly broad limits, warmer fuel is better than cooler fuel. Some systems use a loop off the radiator system to help warm the fuel. No need to cool the fuel, especially with direct contact water.

6 0

3 years ago

Consider a solid round elastic bar with constant shear modulus, G, and cross-sectional area, A. The bar is built-in at both ends

Ierofanga [76]

Answer:

$\t(x)_{max} =\dfrac{p\times L}{2\times \pi}$

Explanation:

Given that

Shear modulus= G

Sectional area = A

Torsional load,

$t(x) = p sin( \frac{2\pi}{ L} x)$

For the maximum value of internal torque

$\dfrac{dt(x)}{dx}=0$

Therefore

$\dfrac{dt(x)}{dx} = p cos( \frac{2\pi}{ L} x)\times \dfrac{2\pi}{L}\\ p cos( \frac{2\pi}{ L} x)\times \dfrac{2\pi}{L}=0\\cos( \frac{2\pi}{ L} x)=0\\ \dfrac{2\pi}{ L} x=\dfrac{\pi}{2}\\\\x=\dfrac{L}{4}$

Thus the maximum internal torque will be at x= 0.25 L

$t(x)_{max} = \int_{0}^{0.25L}p sin( \frac{2\pi}{ L} x)dx\\t(x)_{max} =\left [p\times \dfrac{-cos( \frac{2\pi}{ L} x)}{\frac{2\pi}{ L}} \right ]_0^{0.25L}\\t(x)_{max} =\dfrac{p\times L}{2\times \pi}$

6 0

3 years ago