2. What's true about the elliptical path that the planets follow around the sun? A. A line can be drawn from the planet to the s
2 answers:
You might be interested in
Answer:
a) α = 1.875
b) t = 8 s
Explanation:
Given:
ω1 = 0
ω2 = 15
theta (angular displacement) = 60 rad
*side note: you can replace regular, linear variables in kinematic equations with angular variables (must entirely replace equations with angular variables)*
a) α = ?
(ω2)^2 = (ω1)^2 + 2α(theta)
=
+ 2(α)(60)
225 = 120α
α = 1.875
b)
α = (ω2-ω1)/t
t = (ω2-ω1)/α = (15-0)/1.875 = 8
t = 8 s
Answer:
Explanation:
Given
object of mass m is suspended from spring and set in oscillation with time Period T
We know Time period of a mass in oscillation is given by
where k=spring constant
When mass m is replaced by a mass of 2 m time period is given by
i.e. New time period becomes times of previous one
Answer:
-26 m/s.
Explanation:
Hello,
In this case, since the vertical initial velocity is 26 m/s and the vertical final velocity is 0 m/s at P, we compute the time to reach P:
With which we compute the maximum height:
Therefore, the final velocity until the floor, assuming P as the starting point (Voy=0m/s), turns out:
Which is clearly negative since it the projectile is moving downwards the starting point.
Regards.
Answer:
4515.49484 N
4329.10484 N
Explanation:
r = Radius of balloon = 4.4 m
m = Mass of balloon with instruments = 19 kg
g = Acceleration due to gravity = 9.81 m/s²
Volume of balloon
The Buoyant force = Weight of the air displaced
The buoyant force acting on the balloon is 4515.49484 N
Net force on the balloon
The net force on the balloon is given by 4329.10484 N
As the balloon goes up the pressure outside reduces as the density of air decreases while the air pressure inside the balloon is high hence, the radius of the balloon tend to increase as it rises to higher altitude.