Question

What is the acceleration of a 30.0-kg go kart if the thrust of its engine is 300.0 N?

Answer 1

Answer : $a=10\ m/s^2$

Explanation :

It is given that,

Mass of the engine, m = 30 kg

Thrust is equivalent to the force acting perpendicularly and it is F = 300 N

According to Newton's second law of motion :

$F = m\times a$

a is the acceleration of the engine.

$a=\dfrac{F}{m}$

$a=\dfrac{300\ N}{30\ Kg}$

$a=10\ m/s^2$

So, the acceleration of the engine is $10\ m/s^2$.

Hence, this is the required solution.

Answer 2

Answer:

Acceleration, $a=10\ m/s^2$

Explanation:

It is given that,

Mass of the cart, m = 30 kg

Thurst applied to the engine, F = 300 N

Let a is the acceleration of the cart. According to Newton's second law of motion, force is equal to the product of mass and acceleration. It is given by :

$F=ma$

$a=\dfrac{F}{m}$

$a=\dfrac{300\ N}{30\ kg}$

$a=10\ m/s^2$

So, the acceleration of the cart is $10\ m/s^2$. Hence, this is the required solution.