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sweet-ann [11.9K]
3 years ago
12

What is the acceleration of a 30.0-kg go kart if the thrust of its engine is 300.0 N?

Physics
2 answers:
VikaD [51]3 years ago
5 0

Answer : a=10\ m/s^2

Explanation :

It is given that,

Mass of the engine, m = 30 kg

Thrust is equivalent to the force acting perpendicularly and it is F = 300 N

According to Newton's second law of motion :

F = m\times a

a is the acceleration of the engine.

a=\dfrac{F}{m}

a=\dfrac{300\ N}{30\ Kg}

a=10\ m/s^2

So, the acceleration of the engine is 10\ m/s^2.

Hence, this is the required solution.

sp2606 [1]3 years ago
5 0

Answer:

Acceleration, a=10\ m/s^2

Explanation:

It is given that,

Mass of the cart, m = 30 kg

Thurst applied to the engine, F = 300 N

Let a is the acceleration of the cart. According to Newton's second law of motion, force is equal to the product of mass and acceleration. It is given by :

F=ma

a=\dfrac{F}{m}

a=\dfrac{300\ N}{30\ kg}

a=10\ m/s^2

So, the acceleration of the cart is 10\ m/s^2. Hence, this is the required solution.

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What is the mass of a truck in grams of it produces a force of 1500N while accelerating at a rate of 6 m/s²?​
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Answer:

250,000

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<h2> </h2>

<h2>formula = ( F=ma </h2>

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A 0. 060-kg tennis ball, moving with a speed of 5. 82 m/s , has a head-on collision with a 0. 090-kg ball initially moving in th
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Final speed of the tennis ball, moving with a speed of 5. 82 m/s , has a head-on collision with a 0. 090-kg ball is 2.964 m/s.

<h3>What is conservation of momentum?</h3>

Momentum of an object is the force of speed of it in motion. Momentum of a moving body is the product of mass times velocity. By the law of conservation of momentum,

m_1u_1 + m_2u_2 = (m_1+m_2)v

Here, (m) is the mass, (u) is initial velocity before collision, v is final velocity after collision and (subscript 1, and 2) are used for body 1 and 2 respectively. Rewrite the formula for final velocity as,

v=\dfrac{m_1u_1 + m_2u_2}{(m_1+m_2)}

A 0. 060-kg tennis ball, moving with a speed of 5. 82 m/s, has a head-on collision with a 0. 090-kg ball, initially moving in the same direction at a speed of 3.44 m/s. Thus, the initial velocity of the second ball is,

v_{2f}=5.82+3.44+v_{1f}\\v_{2f}=2.38+v_{1f}

Let v1f is the final velocity of first ball. Thus, the initial velocity of the first ball is,

v_{1f}=\dfrac{(0.060)(5.82) + (0.090)(3.44-2.38)}{(0.060)+(0.090)}\\v_{1f}=2.964\rm\; m/s

Thus, final speed of the tennis ball, moving with a speed of 5. 82 m/s , has a head-on collision with a 0. 090-kg ball is 2.964 m/s.

Learn more about the conservation of momentum here;

brainly.com/question/7538238

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Oh no! The Hulk just fell off the Empire State Building! Calculate how long it took him to fall straight down from the top of th
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