<u>Answer:</u> The standard change in Gibbs free energy for the given reaction is 4.33 kJ/mol
<u>Explanation:</u>
For the given chemical equation:
The expression of for the given reaction:
We are given:
Putting values in above equation, we get:
To calculate the standard Gibbs free energy, we use the relation:
where,
= standard Gibbs free energy
R = Gas constant =
T = temperature =
= equilibrium constant in terms of partial pressure = 0.174
Putting values in above equation, we get:
Hence, the standard change in Gibbs free energy for the given reaction is 4.33 kJ/mol
Answer:
(2) Less than the volume of object b.
Explanation:
1 mL is, by definition, 1cc (cubic centimeter) of water. Therefore if B displaces 15 cc, then its volume is 15. A's volume is cc which is less than 15, so the answer is (2).
Answer:
4, 3, 2
Explanation:
so I would balance this equation first by identifying the 3 2 inbalance
usually with these you find a common factor that suits other variables
eg. 6 so times the right side by 2 and the O2 by 3
now O are equal on both sides and to equalise fe times the left by 4
the equation is balanced
Answer: The kinetic energy of solids is limited to vibrational energies..the particles are tightly bound in their crystalline structure and can only bend, flex, and vibrate about relatively fixed position. When vibrational energies exceed the strength of the force holding the particles together, the crystal structure collapses and we say the material melted. The particles can now have, in addition to its vibrational energies, rotational energy. Chunks of the collapsed crystal can, like a ball floating in water, rotate without showing much translational energy. Generally, we associate solids with vibrational kinetic energy, liquids with rotational kinetic energy, and gases with translational kinetic energy. Actually though, liquids have both vibrational and rotational energies, and gases have all three.
Answer:
0.1 M
Explanation:
Molarity = number of moles / litres of solution.
4 g of calcium bromide = 0.02 mol
(found by dividing 4 g by the atomic mass of CaBr2, which is 199.886)
200 mL of solution = 0.2 litres
Molarity = 0.02 mol / 0.2 L = 0.1 M