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3 years ago

How dose an atom change if all of its electrons are removed

Physics

1 answer:

cluponka [151]3 years ago

7 0

Answer:

The atom becomes a positively charged ion.

Explanation:

The building blocks of an atom are protons, neutrons, and electrons.
The protons and neutrons present in the core of the atom are called nucleus.
The electrons are scattered in an ordered way around the nucleus.
The protons are positively charged and the electrons are negatively charged particles. The neutrons do not possess any charges.
Binding energy is supplied to the atom to remove an electron.
It is possible to remove the electrons of the lighter elements.
When an electron is removed from the hydrogen atom. It becomes positively charged ion or simply proton.
When all of the electrons are removed from the helium atom, it becomes a positively charged α particle.
It is practically very difficult to remove all of the electrons from the heavier elements.
When all of the electrons are removed from an atom it becomes an unstable positively charged ion.

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3 years ago

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3 years ago

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19. The particles in an object move very quickly and are spread apart. Then they move slower and get slower and get closer toget

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Answer:

The transformation went from a gas to a solid which is a Deposition

Explanation:

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3 years ago

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2 years ago

A grasshopper hops along a level road. on each hop, the grasshopper launches itself itself at an angle of 45 degrees. and achiev

Harman [31]

Answer: 1.9 m/s

Explanation:

1) Data:

height, y = 0

range, x = 0.77m

angle, α = 45°

question, horizontal velocity, Vox = ?

2) Physical principles and formulas

Projectile motion.

$y=V_{0y}t-gt^{2} /2\\ \\ x=V_{0x}t\\ \\ V_{0y}=V_0sin\alpha \\ \\ V_{0x}=V_0cos\alpha$

3) Solution

$0.77=V_0cos(45)t\\ t=0.77/(V_0cos(45))$

$y=0=V_0sin(45)t-gt^{2} /2$

Factor

$0=t[V_0sin(45)-gt/2]$

Discard t = 0 and solve for the other factor:

$gt/2=V_0sin(45)\\ \\ V_0= gt/(2sin(45))=9.81[0.77/V_{0}cos(45)]/[2sin(45)]\\ \\ V_0^2=9.81[0.77/(2cos(45)sin(45)=9.81[0.77/sin(90)]=7.55\\ \\ V_0}=\sqrt{7.55} =2.8$

Find Vx:

$Vx=V_{0x}=V_{0}cos(45)=2.75(\sqrt{2} /2]=1.9$

Vx = 1.9m/s ← answer

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3 years ago

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