an object initially traveling at 20 meters per second South accelerates uniformly at 6.0 meters per second squared and is displa
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Answer:
<em>The block hits the ground at 27.9 m/s</em>
Explanation:
<u>Gravitational Potential Energy (GPE)</u>
It's the energy stored in an object because of its height in a gravitational field.
It can be calculated with the equation:
U=m.g.h
Where m is the mass of the object, h is the height with respect to a fixed reference, and g is the acceleration of gravity or .
When the block is at the edge of the cliff it has potential energy that can be transformed into any other type of energy as it starts falling to the ground.
The GPE of the block of mass m=42 Kg at h=40 m is:
U = 42*9.8*40
U = 16,464 J
The block loses 81 J due to air resistance, thus the energy stored when it hits the ground is 16,464 J - 81 J = 16,383 J.
This energy is stored as kinetic energy, whose formula is:
Solving for v:
v = 27.9 m/s
The block hits the ground at 27.9 m/s
To solve this problem we will apply Newton's second law. The second law says that mass by acceleration is equivalent to the Force exerted on a body. Mathematically this
Here,
m = mass
a = Acceleration
The ball flies through the air under the effect of gravity only. Therefore the acceleration is due to gravity, we have that
Then,
Replacing
The negative sign implies that the force acting on the ball is in the downward direction that is towards the negative y direction.