3 years ago

16.

Physics

1 answer:

Sholpan [36]3 years ago

4 0

Answer:

doing her homework/finding time to do important things

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A projectile is fired with an initial speed of 100 m/s and angle of elevation 30 degrees. The projectile eventually hits the gro

zaharov [31]

Answer:

Explanation:

Given

launch velocity $u=100\ m/s$

Launch angle $\theta =30^{\circ}$

Range of Projectile $R=\frac{u^2\sin 2\theta }{g}$

$R=\frac{100^2\times \sin (2\times30)}{9.8}$

$R=883.699\approx 883.7$

Horizontal velocity remain same and only vertical velocity changes.

Initially vertical velocity is in upward direction but as soon as it reaches the ground its direction change but magnitude remain same.

$u_y=100\sin (30)=50\ m/s$

$u_x=100\cos (30)=86.60\ m/s$

$u_{net}=\sqrt{(50)^2+(86.60)^2}$

$u_{net}=99.99\approx 100\ m/s$

7 0

3 years ago