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lesantik [10]
2 years ago
6

A student of weight 627 N rides a steadily rotating Ferris wheel (the student sits upright). At the highest point, the magnitude

of the normal force on the student from the seat is 563 N. (a) What is the magnitude of at the lowest point? If the wheel's speed is doubled, what is the magnitude FN at the (b) highest and (c) lowest point?
Physics
1 answer:
ladessa [460]2 years ago
6 0

Answer:

a)Net force = 691 N

b)Net force = 371 N

c)Net force = 883 N

Explanation:

Weight= 627 N

At the highest point

Net force = Centripetal force + weight

At the highest ,Net force = 563 N.

So

Centripetal force(Fc) = 563 - 627 N

Fc= - 64 N

Negative sign means force is upward.

But at the lowest point

Fc=  64 N

Net force = Centripetal force + weight

Net force = 64 + 627

Net force = 691 N

When speed will become double

We know that

F_c=m\omega ^2r

Then the force Fc will become 4 times.

Fc'= 4 Fc

F'c= 4 x 64 N

F'c= 256 N  

So new Centripetal force'= 256 N  

At the highest point

Net force = Centripetal force' + weight

At the highest point

Net force =-256 + 627

Net force = 371 N

At the lowest point

Net force = Centripetal force' + weight

Net force = 256 + 627

Net force = 883 N

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Answer:

It takes about 88 seconds for the cannonball to reach its maximum height (ignoring air resistance).

Explanation:

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Calculate the final speed of a 110-kg rugby player who is initially running at 8.00 m/s but collides head-on with a padded goalp
Contact [7]
<span>The answer is -0.8 m/s. We know acceleration is the average of final minus initial velocity over time (a = (vf-v0)/t). We also know that Force is equal to Mass times Acceleration (F = ma). Using our force equation, we know that the acceleration we get is negative 8.8 (-8.8). The force is acting in the opposite direction of the rugby player, hence the negative sign. From there, plug in that number for a in the velocity equation, and solve for vf, as v0 and t are known. We get 0.8 m/s in the opposite direction that the player was running.</span>
6 0
2 years ago
(a) Consider a fusion generator built to create 3.00 GW of power. Determine the rate of fuel burning in grams per hour if the DT
Stels [109]

The rate of fuel burning in grams per hour if the DT reaction is used is 1.08 ×10^1^3 J/g per hour

<h3>How is the rate of fuel burning in grams per hour calculated when the D-T reaction is used?</h3>
  • D + T → He + n
  • The D-T fusion reaction results in a Helium (He) and  neutron (n)

E = 17.59 MeV

Mass = 2.014u + 3.016u

= 5.030u

Energy per Kg = (17.59×10^6×1.6×10^-^1^9) ÷ ( 5.030×1.66×10^-^2^7)

= 3.37×10^1^4 J/Kg

= 3.0× 10^9 J/g

Rate of fuel burning in grams per hour = 3.0× 10^9 ×  3600

= 3.6×3.0×10^1^2

= 1.08 ×10^1^3 J/g per hour

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brainly.com/question/13399644

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4 0
2 years ago
A 10 kg box hangs from a rope. What is the tension in the rope (in Newtons) if the box is stationary
Archy [21]

Answer:

T = 98 N

Explanation:

The gravity of the earth is known to be 9.8 m/s²

Data:

  • m = 10 kg
  • g = 9.8 m/s²
  • T = ?

Use formula:

  • \boxed{\bold{T=m*g}}

Replace and solve:

  • \boxed{\bold{T=10\ kg*9.8\frac{m}{s^{2}}}}
  • \boxed{\boxed{\bold{T=98\ N}}}

The tension in the rope is <u>98 Newtons.</u>

Greetings.

5 0
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Which term describes the time it takes for an object to complete one full cycle of motion on a spring?
Sav [38]

The term period (symbol: T) describes the time it takes for an object to complete one full cycle of motion on a spring.

The formula for time is: T  = 1 / f , where f is the frequency  , f= c / λ = wave speed c (m/s) / wavelength λ (m)..

The formula describes that as the frequency of a wave increases, the time period of the wave decreases.

4 0
3 years ago
Read 2 more answers
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