Question

When the speed of the bottle is 2 m/s, the KE is kg m2/s2. When the speed of the bottle is 3 m/s, the KE is kg m2/s2. When the speed of the bottle is 4 m/s, the KE is kg m2/s2. When the speed of the bottle is 5 m/s, the KE is kg m2/s2. When the speed of the bottle is 6 m/s, the KE is kg m2/s2.
instructions
In this part of the experiment, you will be changing the speed of the bottle by dropping it from different heights. You will use the same mass, 0.250 kg, for each trial, so record this mass in Table B for each velocity. Then, calculate the expected kinetic energy (KE) at each velocity. Use the formula KE = mv2,
where m is the mass and v is the speed. Record your calculations in Table B of your Student Guide.

Answer 1

Answer with Explanation

Record your calculations in Table B of your Student Kinetic energy is the half of the product of mass and square of velocity. If the mass is given which is 0.250 kg. By putting values in the formula we will get values of the kinetic energy of different speeds. Kinetic energy depends upon the mass and velocity of the objects. When the speed of the bottle is 2 m/s, the KE is kg m2/s2. When the speed of the bottle is 3 m/s, the KE is kg m2/s2. When the speed of the bottle is 4 m/s, the KE is kg m2/s2. When the speed of the bottle is 5 m/s, the KE is kg m2/s2. When the speed of the bottle is 6 m/s, the KE is kg m2/s2.                                                                                                                                                    

MASS(kg)      SPEED(m/s)       FORMULA       KINETIC ENERGY(kgm2/s2)

0.250                   2                = ½ (0.250)(2)^2                0.5

0.250                   3                = ½ (0.250)(3)^2               1.125

0.250                   4                = ½ (0.250)(4)^2.                2

0.250                   5                = ½ (0.250)(5)^2               3.125

0.250                   6                = ½ (0.250)(6)^2                 4.5

Answer 2

mass of the bottle in each case is M = 0.250 kg

now as per given speeds we can use the formula of kinetic energy to find it

1) when speed is 2 m/s

kinetic energy is given as

$K = \frac{1}{2}mv^2$

$K = \frac{1}{2}(0.250)(2)^2 = 0.5 J$

2) when speed is 3 m/s

kinetic energy is given as

$K = \frac{1}{2}mv^2$

$K = \frac{1}{2}(0.250)(3)^2 = 1.125 J$

3) when speed is 4 m/s

kinetic energy is given as

$K = \frac{1}{2}mv^2$

$K = \frac{1}{2}(0.250)(4)^2 = 2 J$

4) when speed is 5 m/s

kinetic energy is given as

$K = \frac{1}{2}mv^2$

$K = \frac{1}{2}(0.250)(5)^2 = 3.125 J$

5) when speed is 6 m/s

kinetic energy is given as

$K = \frac{1}{2}mv^2$

$K = \frac{1}{2}(0.250)(6)^2 = 4.5 J$