formula for gravitational P.E =mgh
Solution:-mass=3kg height=5metre and gravity=9.8 or 10m/sec² so P.E=mgh , 3×9.8×5=147kgm²/sec²
Answer:
The final temperature of the gas is <em>114.53°C</em>.
Explanation:
Firstly, we calculate the change in internal energy, ΔU from the first law of thermodynamics:
ΔU=Q - W
ΔU = 1180 J - 2020 J = -840 J
Secondly, from the ideal gas law, we calculate the final temperature of the gas, using the change in internal energy:


Then we make the final temperature, T₂, subject of the formula:



Therefore the final temperature of the gas, T₂, is 114.53°C.
The heat capacity and the specific heat
Answer:

Explanation:
Given that,
The magnitude of magnetic field, B = 2.21
We need to find the magnitude of the electric field. Let it is E. So,

Put all the values,

So, the magnitude of the electric field is equal to
.
V = [4/3]π r^3 => [dV / dr ] = 4π r^2
[dV/dt] = [dV/dr] * [dr/dt]
[dV/dt] = [4π r^2] * [ dr/ dt]
r = 60 mm, [dr / dt] = 4 mm/s
[dV / dt ] = [4π(60mm)^2] * 4mm/s = 180,955.7 mm/s