Answer:
Magnitude of the magnetic field inside the solenoid near its centre is 1.293 x 10⁻³ T
Explanation:
Given;
number of turns of solenoid, N = 269 turn
length of the solenoid, L = 102 cm = 1.02 m
radius of the solenoid, r = 2.3 cm = 0.023 m
current in the solenoid, I = 3.9 A
Magnitude of the magnetic field inside the solenoid near its centre is calculated as;
Where;
μ₀ is permeability of free space = 4π x 10⁻⁷ m/A
Therefore, magnitude of the magnetic field inside the solenoid near its centre is 1.293 x 10⁻³ T
Answer:
C. 
Explanation:
Let initial charges on both spheres be,
When the sphere C is touched by A, the final charges on both will be,
#Now, when C is touched by B, the final charges on both of them will be:
Now the force between A and B is calculated as:
Hence the electrostatic force becomes 3F/8
Answer:
Oooo someone is writing a answer. (Also im new to this so Idk what to really do.)
Explanation:
Answer:
Initial velocity will be 1.356 m/sec
Explanation:
Let the initial speed = u
Angle at which rubber band is launched = 37°
Horizontal component of initial velocity 
Time is given as t = 1.20 sec
Distance in horizontal direction = 1.30 m
We know that distance = speed × time
So time 
So initial velocity will be 1.356 m/sec
