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iris [78.8K]
3 years ago
9

Which of these is at thermal equilibrium?A- 25° 5°B- 25° 25°C- 5° 5°D- 5° 25°​

Physics
1 answer:
Lady_Fox [76]3 years ago
5 0

Answer:

B

Explanation:

there must not be any heat transfer

You might be interested in
Recall that if a line is parallel to the vector v and passes through the point P0, which is the tip of the position vector r0, t
Elenna [48]

Answer:

The vector equation of the line is

                                \overrightarrow{r}=+t

Parametric equations for given line are

                                       x=7+t\\y=-8+6t\\z=3-13t

Explanation:

The vector equation of the line is given by

                                     r(t) = r_{o} + tv

r₀ = (7, -8, 3)

v = (1, 6, -13)

At these points the vector equation for this line is:

\overrightarrow{r}=\overrightarrow{r_{o}}+t\overrightarrow{v}\\\overrightarrow{r}=+t

Parametric equations for given line are

                                       x=7+t\\y=-8+6t\\z=3-13t

8 0
3 years ago
how many meters would you have traveled after 90 minutes if you're average velocity is 4 kilometers per hour?​
Gekata [30.6K]

Answer:

<h2><em><u>6,000 Meters.</u></em></h2>

Hope this helps you! :)

5 0
3 years ago
Help me please, ;) I could use it
erastova [34]

Answer:

The solution(s) are in order with respect to the attachments

2.613\:\cdot10^5 Joules ; 5. Adding the same amount of heat to two different objects will produce the same increase in temperature ; 2. Same speed in both ; 2. A

Explanation:

Diagram 1 ( Liquid Nitrogen ) : So as you can see, we want our units in Joules here, and can therefore multiply the mass of gaseous nitrogen and the latent heat of liquid nitrogen, to cancel the units kg, and receive our solution - in terms of Joules. Let's do it.

q ( energy removed ) = mass of nitrogen * latent heat of liquid nitrogen,

q = 1.3 kg * 2.01 * 10⁵ J / kg = 1.3\:\cdot \:2.01\:\cdot \:\:10^5 = 10^5\cdot \:2.613 = 100000\cdot \:2.613 = 261300 Joules = 261.3 kiloJoules = 2.613 * 10⁵Joules is the energy that must be removed

Diagram 2 : The same amount of heat does not necessarily mean the same increase in temperature for two different objects. The increase in temperature depends on the specific heat capacity of the substance. Therefore your solution is 5 ) Adding the same amount of heat to two different objects will produce the same increase in temperature.

Diagram 3 : The temperatures in both glasses are the same, and hence the molecules have the same average speed. Therefore your solution is 2 ) Same speed in both.

Diagram 4 : Glass A has more water molecules, and hence has more thermal energy. Your solution is 2 ) A.

7 0
3 years ago
Read 2 more answers
A teacher wants to perform a classroom demonstration that illustrates both chemical and physical changes. Which would be the bes
anygoal [31]

Answer

D) burning a candle

Explanation

When burning a candle no new substance is form.

We have both physical and chemical change occuring.

Physical part: Melting of the solid wax and evaporation of the liquid forms the physical change.

Chemical part: burning of the wax vapour forms the chemical change.

7 0
3 years ago
Read 2 more answers
F all of the energy in a falling object's gravitational potential energy store is transferred to its kinetic energy store by the
stepladder [879]

Answer:

The options are not shown, so let's derive the relationship.

For an object that is at a height H above the ground, and is not moving, the potential energy will be:

U = m*g*H

where m is the mass of the object, and g is the gravitational acceleration.

Now, the kinetic energy of an object can be written as:

K = (1/2)*m*v^2

where v is the velocity.

Now, when we drop the object, the potential energy begins to transform into kinetic energy, and by the conservation of the energy, by the moment that H is equal to zero (So the potential energy is zero) all the initial potential energy must now be converted into kinetic energy.

Uinitial = Kfinal.

m*g*H = (1/2)*m*v^2

v^2 = 2*g*H

v = √(2*g*H)

So we expressed the final velocity (the velocity at which the object impacts the ground) in terms of the height, H.

5 0
3 years ago
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