Answer:
so length of the fence is 250 feet
Explanation:
Given data
fencing (L) = 500 feet
enclose the garden = 3 sides
to find out
length of the fence
solution
we consider barn length x and width y
so we say x +2y = 500 ........1
we want to maximize length i.e xy = f
so we say
df/dx = ƛ × dL/dx
y = ƛ × 1
and
df/dy = ƛ × df/dy
x = ƛ × 2
from equation 1 we can say
2 ƛ + 2 ƛ = 500
so ƛ = 500/4 = 125
so that x = 2× 125 , y = 125
so x = 250 , y = 125
so length of the fence is 250 feet
Complete Question
An isolated charged soap bubble of radius R0 = 7.45 cm is at a potential of V0=307.0 volts. V0=307.0 volts. If the bubble shrinks to a radius that is 19.0%19.0% of the initial radius, by how much does its electrostatic potential energy ????U change? Assume that the charge on the bubble is spread evenly over the surface, and that the total charge on the bubble r
Answer:
The difference is 
Explanation:
From the question we are told that
The radius of the soap bubble is 
The potential of the soap bubble is 
The new radius of the soap bubble is 
The initial electric potential is mathematically represented as
The final electric potential is mathematically represented as
The initial potential is mathematically represented as

The final potential is mathematically represented as

Now

substituting values

=> 
So
Therefore
where k is the coulomb's constant with value 
substituting values

Answer:
G M m / R^2 = F force of attraction for proton
K e^2 / r^2 = F force of attraction between 2 protons
G M m / R^2 = K e^2 / r^2
r^2 = K e^2 R^2 / (G M m)
r^2 = 9E9 * (1.6E-19)^2 * (6.37E6)^2 / (6.67E-11 * 5.98E24 * 1.7E-27)
r^2 = 9 * 2.56 * 40.6 / (6.67 * 5.98 * 1.7) * 10^-19
r^2 = 1.38 * 10^-30
r = 1.17E-15 m
Answer:
The net charge on the shell is 30x10^-9C
Explanation:
Pls see attached file