Answer:
317 g
Explanation:
Cu + 2HCl --> CuCl2 +H2
1 : 2 1 : 1
1 mole of Cu = 63.5 g
1 mole of H2 = 2g
1 mole Cu produces = 1 mole of H2
63.5 g of Cu produces = 2 g of H2
So
10 g of H2 will be produced from = (63.5/2)*10 = 317 g of Copper
There should be 26.08 grams.
Answer:
0.36 N
Explanation:
Let's consider the neutralization between HBr and NaOH.
HBr + NaOH → NaBr + H₂O
The equivalents of NaOH that reacted are:
24.0 × 10⁻³ L × 1.5 eq/L = 0.036 eq
Since the reactions are equivalent to equivalent, also 0.036 equivalents of HBr reacted.
The normality of HBr is:
N = 0.036 eq / 0.100 L = 0.36 N
