Answer:
142.36 kg
Explanation:
volume of water in the lake = surface area x depth
= 18.5 x ( 1760 x 3 )² x 39 ft³
= 2.011 x 10¹⁰ ft³
= 2.011 x 10¹⁰ x 28.3168 liter .
= 56.945 x 10¹⁰ liter .
concentration of mercury = .25 x 10⁻⁶ g / liter
= 25 x 10⁻⁸ g / liter
= 25 x 10⁻¹¹ kg / liter
mass of mercury in the water of lake
= 25 x 10⁻¹¹ x 56.945 x 10¹⁰ kg
= 142.36 kg .
51.3 gram of water should form if 32.5 g of NH₃ react with enough oxygen.
<h3>How to find the Number of moles ?</h3>
To calculate the number of moles use the formula
Number of moles = 
= 
= 1.9 mol
4NH₃ + 5O₂ → 4NO + 6H₂O
4 mol of NH₃ react with oxygen to given 6 mole of water.
So 1.9 mol of NH₃ produces = 
= 2.85 mol of water
Mass of water = Molar Mass of water × Number of moles of water
= 18 × 2.85
= 51.3 gram
Thus from the above conclusion we can say that 51.3 gram of water should form if 32.5 g of NH₃ react with enough oxygen.
Learn more about the Moles here: brainly.com/question/15356425
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Mass number = protons + neutrons
protons = electrons
so 35 electrons = 35 protons
So 35 protons + 45 neutrons =
80
The element is Bromine with the symbol: Br
2KClO3 --> 2KCl + 3O2
3 moles of oxygen are produced when 2 mol of potassium chlorate (KClO3) decompose.