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3 years ago

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What is arranged to form a material with a crystal structure

1 answer:

mafiozo [28]3 years ago

3 0

Answer:

A crystal or crystalline solid is a solid material whose constituents (such as atoms, molecules, or ions) are arranged in a highly ordered microscopic structure, forming a crystal lattice that extends in all directions. The scientific study of crystals and crystal formation is known as crystallography.

Explanation:

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Copper(I) ions in aqueous solution react with NH 3 ( aq ) according to Cu + ( aq ) + 2 NH 3 ( aq ) ⟶ Cu ( NH 3 ) + 2 ( aq ) K f

Kruka [31]

Answer:

53.18 gL⁻¹

Explanation:

Given that:

$Cu^{2+}_{(aq)}$ $+$ $2NH_{3(aq)}$ $------>$ $[Cu(NH_3)_2]^+_{(aq)}$ ------equation (1)

where;

Formation Constant $(k_f) =$ $6.3*10^{10}$

However, the Dissociation of $CuBr_{(s)$ yields:

$CuBr_{(s)}$ ⇄ $Cu^{+}_{(aq)}$ $+$ $Br^-_{(aq)}$ -------------- equation (2)

where;

the Solubility Constant $(k_{sp})$ $= 6.3 *10^{-9$

From equation (1);

$(k_f) =$ $\frac{[[Cu(NH_3)_2]^+]}{[Cu^{2+}][NH_3]^{2}}$ --------- equation (3)

From equation (2)

$(k_{sp})$ $= [Cu^+][Br^-]$ --------- equation (4)

In $NH_3$ , the net reaction for $CuBr_{(s)$ can be illustrated as:

$CuBr_{(s)$ $+$ $2NH_{3(aq)}$ ⇄ $[Cu(NH_3)_2]^+_{(aq)}$ $+ Br^-_{(aq)}$

The equilibrium constant (K) can be written as :

$K=$ $\frac{[[Cu(NH_3)_2]^+][Br^-]}{[NH_3]^2}$

If we multiply both the numerator and the denominator with $[Cu^+]$ ; we have:

$K=$ $\frac{[[Cu(NH_3)_2]^+][Br^-]}{[NH_3]^2}*\frac{[Cu^+]}{[Cu^+]}$

$K=$ $\frac{[[Cu(NH_3)_2]^+}{[NH_3]^2[Cu^+]}*{[Cu^+][Br^-]}$

$K = k_f *k_{sp}$

$K= (6.3*10^{10})*(6.3*10^{-9})$

$K= 3.97*10^2$

$K$ ≅ $4.0*10^2$

Now; we can re-write our equilibrium constant again as:

$K=$ $\frac{[[Cu(NH_3)_2]^+][Br^-]}{[NH_3]^2}$

$4.0*10^2 = \frac{(x)(x)}{(0.76-2x)^2}$

$4.0*10^2 = \frac{(x)^2}{(0.76-2x)^2}$

$4.0*10^2 = (\frac{(x)}{(0.76-2x)})^2$

By finding the square of both sides, we have

$\sqrt {4.0*10^2} = \sqrt {(\frac{(x)}{(0.76-2x)})^2$

$2.0*10 = \frac{x}{(0.76-2x)}$

$20(0.76-2x) =x$

$15.2 -40x=x$

$15.2 = 40x +x$

$15.2 = 41x$

$x = \frac{15.2}{41}$

$x = 0.3707 M$

In gL⁻¹; the solubility of $CuBr_{(s)$ in 0.76 M $NH_3$ solution will be:

$= \frac{0.3707 mole of CuBr}{1L}*\frac{143.45 g}{mole of CuBr}$

= 53.18 gL⁻¹

4 0

3 years ago

An equilibrium mixture of N2, O2and NO gases at 1500K is determined to consist of 6.4 x 10-3Mof N2, 1.7 x 10-3M O2, and 1.1 x 10

sp2606 [1]

Answer

Explanation:O2 = 1.7×10-3M;

N2 = 6.4×10-3M;

NO = 1.1 10-5M.

4 0

3 years ago

What is disproportionation reaction and give one example of it ?

mario62 [17]

Answer:

A disproportionation reaction is when a multiatomic species whose pertinent element has a specific oxidation state gets oxidized and reduced in two separate half-reactions, yielding two other products containing the same pertinent element. A convenient example is Mn2O3 becoming Mn2+ and MnO2 .

4 0

3 years ago

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Which of the following bases can remove a proton from formic acid in a reaction that favors products?

Debora [2.8K]

Hydroxide ion is a strong and would react with H+ to form water

OH-+H+---->H2O

7 0

3 years ago

This is a science question for k12

bixtya [17]

Height of wave - amplitude

Higher the pitch - higher the frequency

Louder - higher the amplitude

bottom of the wave - trough

distance from crest to crest - wave length

top of the wave - crest

6 0

2 years ago

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