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dolphi86 [110]
3 years ago
11

Calculate the molar mass of a gas

Chemistry
1 answer:
spin [16.1K]3 years ago
4 0

Answer:

MOLAR MASS = 32 g/mol

Explanation:

Condition of standard temperature and pressure(STP) are as follow:

Temperature = 273 K

Pressure = 1 atm (or 100000 Pa)

Here atm is atmosphere and Pa is Pascal

STP conditions arte used for measuring gas density and volume using Ideal Gas Law.Here 1 mole of ideal gas occupies 22.4 L of volume.

According toi Ideal Gas Equation :

PV = nRT

where P = pressure, n= number of moles, V = volume ,R= Ideal Gas Constant and T= temperature

n=\frac{PV}{RT}

From question:

V=280 ml = 0.28 L

P = 1 atm

R=0.08205 L atm/K mol

T=273 K

Putting values in above formula :

n=\frac{1\times .280}{0.08205\times 273}

n = 0.0125 moles

Now n=\frac{given\ mass}{Molar\ mass}

Molar\ mass=\frac{given\ mass}{n}

given mass = 0.4 g (given)

Molar\ mass=\frac{0.4}{0.0125}

On solving we get:

Molar mass = 32 g/mol

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3 years ago
Write the balanced molecular, ionic, and net ionic equations for the reaction when a solution of lithium phosphate is mixed with
Kaylis [27]

Answer:

see explaination

Explanation:

Molecular equation;

2Li3PO4(aq) + 3CaCl2(aq) >>>> Ca3(PO4)2(s) + 6LiCl(aq)

Total ionic equation; . Includes all ions ;

6Li^+(aq) + 2PO4^-3(aq) + 3Ca^+2(aq) + 6Cl^-(aq) >>>> Ca3(PO4)2(s) + 6Li^+(aq) + 6Cl^-(aq)

Net ionic equation; remove common ions from total ionic;

2PO4^-3(aq) + 3Ca^+2(aq) >>>> Ca3(PO4)2(s)

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3 years ago
What feature of an orbital is related to each of the following?<br> (a) Principal quantum number (n)
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Principle  quantum number describes the energy of an electron and most probable distance of the electron from the nucleus.

<h3>What is the significance of principle quantum numbers and azimuthal quantum numbers?</h3>

A principal quantum number  signifies size and energy of the orbital.Azimuthal quantum number signifies three dimensional shape of the orbital.

Magnetic quantum numbers signifies spatial orientation of the orbital.

Principal quantum numbers is the quantum numbers denoted by n which indirectly describes the size of the electron orbitals. It is always assigned an integer value but its value never be 0.  The feature of a principal quantum numbers  is the energy of  an electron and  most probable distance of the electron from the nucles.

to learn more about Principal quantum numbers click here brainly.com/question/16979660

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6 0
2 years ago
Student carries out a titration to determine the concentration of a solution of
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The concentration of the Nitric acid solution : 0.114 M

<h3>Further explanation  </h3>

Titration is a procedure for determining the concentration of a solution (analyte) by reacting with another solution whose known concentration (usually a standard solution) is called the titrant. Determination of the endpoint/equivalence point of the reaction can use indicators according to the appropriate pH range  

Titrations can be acid-base titration, depositional titration, and redox titration. An acid-base titration is the principle of neutralization of acids and bases  

Reaction

HNO₃ + NaOH → NaNO₃ + H₂O​

Concentration a standard solution  of sodium hydroxide :  0.0998 mol/dm³ , and the volume = 25 cm³

moles NaOH=

\tt mol=M\times V\\\\mol=0.0998\times 25\\\\mol=2.495~mlmoles

<em>From the equation, mol ratio HNO₃ : NaOH = 1 : 1, so mol HNO₃ = mol NaOH=</em><em>2.495 mlmoles</em>

<em></em>

The volume of HNO₃ = 21.8 cm³, so the concentration :

\tt M=\dfrac{n}{V}\\\\M=\dfrac{2.495}{21.8}\\\\M=0.114

7 0
3 years ago
A 4.0 L balloon has a pressure of 406 kPa. When the pressure increases to 2,030 kPa, what is the volume? *
elena-14-01-66 [18.8K]

The new volume when pressure increases to 2,030 kPa is 0.8L

BOYLE'S LAW:

The new volume of a gas can be calculated using Boyle's law equation:

P1V1 = P2V2

Where;

  1. P1 = initial pressure (kPa)
  2. P2 = final pressure (kPa)
  3. V1 = initial volume (L)
  4. V2 = final volume (L)

According to this question, a 4.0 L balloon has a pressure of 406 kPa. When the pressure increases to 2,030 kPa, the volume is calculated as:

406 × 4 = 2030 × V2

1624 = 2030V2

V2 = 1624 ÷ 2030

V2 = 0.8L

Therefore, the new volume when pressure increases to 2,030 kPa is 0.8L.

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