Answer:
Explanation:
The forces exerted by each mass is best understood in terms of their momentum.
Momentum is a sort of compelling force or impulse. It is given as:
Momentum = mass x velocity
Let us consider the momentum of the balls;
Substance C;
Mass = 1kg
Velocity = 5m/s
Momentum of C = 1 x 5 = 5kgm/s
Substance D:
Mass = 100kg
Velocity = 5m/s
Momentum of D = 100kg x 5m/s = 500kgm/s
Body D has a higher momentum compared to Body C. This suggests that body D will exert a higher force than C when they collide.
The higher the momentum, the more the force of impact it has.
Answer:
c they obey inverse square law
Answer:
The car manufacturers could increase bore of the cylinders, place the engine in the center or back of the car, add 1 to 2 turbochargers, and lower the center of gravity of the vehicle to increase traction.
Explanation:
Turbochargers would be recommended because they significantly increase both the torque of the engine as well as the amount of horses powering the car while also increasing original efficiency both with and without the additional power. Weight adjustment allows for lightweight vehicles with good traction. This is important to both keep control of the car under acceleration, but it also makes the vehicle more efficient due to the now sheddable unnecessary weight. A more obvious approach would be to increase the base horsepower and torque of the engine by increasing the bore of the cylinders and the weight of the pistons. This acts as an inertial lever, because the extra piston weight will drag the crankshaft faster. This could also be achieved by taking away piston weight, but this could be catastrophic should a piston slip.
Answer:
(a) 37.5 kg
(b) 4
Explanation:
Force, F = 150 N
kinetic friction coefficient = 0.15
(a) acceleration, a = 2.53 m/s^2
According to the newton's second law
Net force = mass x acceleration
F - friction force = m a
150 - 0.15 x m g = m a
150 = m (2.53 + 0.15 x 9.8)
m = 37.5 kg
(b) As the block moves with the constant speed so the applied force becomes the friction force.
Position of B :
x = 4.66*cos 30 = 4.036
y = 3-4.66*sin 30 = 3-2.33 = 0.67
BC = √y^2+(x-1)^2 = √0.67^2+3.036^2 = 3.109
heading = arctan y/(x-1) = arctan 0.67/(3.036) = 12.44° south of west
hope this helps :)
