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3 years ago

What is the best definition for a minor character

Physics

2 answers:

Anna [14]3 years ago

8 0

Answer:

Minor character definition

A minor character is a character who has a name and does stuff that contributes to the plot, but they aren’t the main characters.

Explanation:

Hope this helps

sergejj [24]3 years ago

7 0

Minor characters. These are the other characters in a story. They are not as important as the major characters, but still play a large part in the story. Their actions help drive the story forward. They may impact the decisions the protagonist or antagonist make, either helping or interfering with the conflict.

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I WILL GIVE BRAINLIEST Which of the following statements is true with regard to transverse and longitudinal waves?

pishuonlain [190]

Answer: Transverse waves have motion perpendicular to velocity, while longitudinal waves have motion parallel to velocity.

Explanation:

Transverse waves are characterized by the fact that the particles of the medium in which they propagate move transversely to the direction of propagation of the wave.

In other words, its displacement is perpendicular to the direction of propagation of the wave, being a good example the circular waves in the water.

On the other hand, Longitudinal waves are characterized by the fact that the oscillation of the particles in the medium is parallel to the direction of propagation of the wave. A good example of this is the sound wave.

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3 years ago

PLEASE HELP ME ASAP! IS MY ANSWER CORRECT?

Flura [38]

No. The correct answer is A.

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2 years ago

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A man releases a stone ar the top edge of a tower during the last second of its travel the stone falls through a distance of (9/

Musya8 [376]

Equations of motion (EoM) use EoM v2=u2+2ax to establish velocities at positions shown in blue in drawing from EoM v=u+at for final 1 second of flight time, we can say v=u+g(1) 2gH−−−−√=2g1625H−−−−−−√+g then, solve for H [in terms of g]

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2 years ago

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Electric fields up to 2.00 × 10 5 N/C have been measured inside of clouds during electrical storms. Neglect the drag force due t

katrin2010 [14]

Answer:

$1.9161676647\times 10^{13}\ m/s^2$ or $1.9532799844\times 10^{12}g$

23.4843749996 m

Yes

Explanation:

E = Electric field = $2\times 10^5\ N/C$

c = Speed of light = $3\times 10^8\ m/s$

m = Mass of proton= $1.67\times 10^{-27}\ kg$

q = Charge of electron = $1.6\times 10^{-19}\ C$

Acceleration is given by

$a=\dfrac{Eq}{m}\\\Rightarrow a=\dfrac{2\times 10^5\times 1.6\times 10^{-19}}{1.67\times 10^{-27}}\\\Rightarrow a=1.9161676647\times 10^{13}\ m/s^2$

Dividing by g

$\dfrac{a}{g}=\dfrac{1.9161676647\times 10^{13}}{9.81}\\\Rightarrow a=1.9532799844\times 10^{12}g$

The acceleration is $1.9161676647\times 10^{13}\ m/s^2$ or $1.9532799844\times 10^{12}g$

$v^2-u^2=2as\\\Rightarrow s=\dfrac{v^2-u^2}{2a}\\\Rightarrow s=\dfrac{(0.1\times 3\times 10^8)^2-0^2}{2\times 1.9161676647\times 10^{13}}\\\Rightarrow s=23.4843749996\ m$

The distance is 23.4843749996 m

The gravitational field is very small compared to the electric field so the effects of gravity can be ignored.

5 0

3 years ago

A set of electric trains are powered by a 9 V battery. What is the resistance of the trains if they draw 4.0 A of current?

Dimas [21]

Answer:

2.25 Ω

Explanation:

Standard equation

V = IR re-arrange to

V /I = R then sub in the values given

9 / 4 = 2.25 Ω

8 0

1 year ago