A yellow ball with a mass of 2 kg is rolling across the floor at 3 m/s. A red ball with a mass of 3 kg is rolling across the sam
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Answer:
the distance between the submarine and the ocean floor is 11,250 m
Explanation:
Given;
speed of the wave, v = 1500 m/s
time of motion of the wave, t = 15 s
The time taken to receive the echo is calculated as;
Therefore, the distance between the submarine and the ocean floor is 11,250 m
As per FBD while its accelerating upwards
we can say that
here normal force is given as
now mass is given as
now we will have
Now while accelerating downwards we can say by FBD
again plug in all values
Red Skull's relative velocity to Captain America, towards the left front of the
truck is approximately <u>33.23 m/s</u> in a direction from the North of
approximately <u>9.18°</u>.
Reasons:
Assumptions;
Taking the north direction as positive.
The activity takes place on the trucks.
The trucks are moving towards each other.
Solution:
Vector form of net speed of Red Skull, is given as follows;
- v₁ = -(
× 3.5)·i + (
Vector form of the net speed of Captain America is given as follows;
- v₂ = (
Relative velocity, v₁₂ = v₁ - v₂
∴ v₁₂ = (-( × 3.5) - (
× 4.0))·i + ((
× 3.5 + 12.5) + (
× 4.0 + 15))·j
- v₁₂ =
·i +
·j
Red Skull's velocity relative to Captain America, v₁₂ = ·i +
·j
- v₁₂ ≈ -5.3·i + 32.8·j
Therefore;
- Red Skull appears to be moving West at <u>5.3 m/s</u> and North at <u>32.8 m/s</u>
- The direction is
Therefore;
- Red Skull appear to be moving at 90° - 80.2° ≈ 9.18° towards the left front end of the truck moving North
The magnitude of the velocity, |v₁₂|, is given as follows;
·
The magnitude of Red Skull's velocity relative to Captain America is,
therefore;
|v₁₂| ≈ <u>33.23 m/s</u>
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