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Aleks04 [339]
3 years ago
7

A yellow ball with a mass of 2 kg is rolling across the floor at 3 m/s. A red ball with a mass of 3 kg is rolling across the sam

e floor at 3 m/s. Which ball has greater kinetic energy, and why?
Physics
2 answers:
Darina [25.2K]3 years ago
7 0

Answer:

The red ball has greater kinetic energy because it is moving at the same speed as the yellow ball, which is lighter than the red ball.

Explanation:

Formula for kinetic energy: 1/2mv²

Yellow ball:

= 1/2(2)(3)²

=1/2(2)(9)

= 9J

Red ball:

= 1/2(3)(3)²

=1/2(3)(9)

= 13.5J

kifflom [539]3 years ago
3 0

Answer:

The red ball has greater kinetic energy, because it has a greater mass.

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An electron with charge −e and mass m moves in a circular orbit of radius r around a nucleus of charge Ze, where Z is the atomic
shepuryov [24]

Answer:

v=\sqrt{\frac{kZe^2}{mr}}

Explanation:

The electrostatic attraction between the nucleus and the electron is given by:

F=k\frac{(e)(Ze)}{r^2}=k\frac{Ze^2}{r^2} (1)

where

k is the Coulomb's constant

Ze is the charge of the nucleus

e is the charge of the electron

r is the distance between the electron and the nucleus

This electrostatic attraction provides the centripetal force that keeps the electron in circular motion, which is given by:

F=m\frac{v^2}{r} (2)

where

m is the mass of the electron

v is the speed of the electron

Combining the two equations (1) and (2), we find

k\frac{Ze^2}{r^2}=m\frac{v^2}{r}

And solving for v, we find an expression for the speed of the electron:

v=\sqrt{\frac{kZe^2}{mr}}

6 0
3 years ago
Metal sphere A has a charge of − Q . −Q. An identical metal sphere B has a charge of + 2 Q . +2Q. The magnitude of the electric
Goshia [24]

Complete Question:

Metal sphere A has a charge of − Q . −Q. An identical metal sphere B has a charge of + 2 Q . +2Q. The magnitude of the electric force on sphere B due to sphere A is F . F. The magnitude of the electric force on sphere A due to sphere B must be:

A. 2F

B. F/4

C. F/2

D. F

E. 4F

Answer:

D.

Explanation:

If both spheres can be treated as point charges, they must obey the Coulomb's law, that can be written as follows (in magnitude):

F =\frac{kQ*2Q}{r^{2} }

As it can be seen, this force is proportional to the product of the charges, so it must be the same for both charges.

As this force obeys also the Newton's 3rd Law, we conclude that the magnitude of the electric force on sphere A due to sphere B, must be equal to the the magnitude of the force on the sphere B due to the sphere A, i.e., just F.

3 0
3 years ago
7. Sanitizing method that are uses chlorine, iodine, and quaternary ammonium. A. ) heat C.) cooking B) chemicals D.) detergent​
AleksandrR [38]

Answer:

Chemicals

Explanation:

Sanitizing method that are uses chlorine, iodine, and quaternary ammonium is <u>chemicals</u>.

Extra Info : -

Sanitizing is also achieved through the use of chemical compounds capable of destroying disease causing bacteria. Common sanitizers are chlorine (bleach), iodine, and quaternary ammonium. Chemical sanitizers have found widespread acceptance in the food service industry.

7 0
2 years ago
3. Ecology
Korvikt [17]

Answer:

The family would not have hot water unless they were to heat the the water. They would have to depend on the stove in order to survive by heating the house to say alive and not freeze. They would also have to depend on the stove to get hot water to do any, but if the sun goes away for too long and everything starts to die then they will have to use what food and wood that they have in order to survive.

Explanation:

6 0
3 years ago
An AM radio transmitter broadcasts 63.2 kW of power uniformly in all directions. (a) Assuming all of the radio waves that strike
egoroff_w [7]

Answer:

Intensity of the transmitted radio wave is 5.406 x 10⁻⁶ W/m²

Explanation:

Given;

power of radio transmitter, P = 63.2 kW = 63200 W

distance of transmission, r = 30.5 km

Intensity of the transmitted radio wave is calculated as follows;

I = \frac{P}{4\pi r^2}

where;

I is the intensity of the transmitted radio wave

Substitute the given values and calculate the intensity of the transmitted radio wave;

I = \frac{P}{4\pi r^2} = \frac{63200}{4\pi (30500)^2} = 5.406 *10^{-6} \ W/m^2

Therefore, Intensity of the transmitted radio wave is 5.406 x 10⁻⁶ W/m²

6 0
3 years ago
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