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Lesechka [4]
3 years ago
9

Yo 20 points no links plz

Physics
2 answers:
makvit [3.9K]3 years ago
8 0

Answer:

he movement of the plates creates three types of tectonic boundaries: ... Where plates serving landmasses collide, the crust crumples and buckles into mountain ranges. ... where two plates grind past each other along what are called strike-slip faults. These boundaries don't produce spectacular features like mountains or ...

Explanation:

asambeis [7]3 years ago
7 0

Answer: Describe how plates create mountain ranges like the Himalayas.

Answer- Most of the world's largest mountains form as plates collide at convergent plate boundaries. This creates mountains. Folding and faulting in these collision zones makes the crust thicker. The world's highest mountain range, the Himalayas, is growing as India collides with Eurasia

2. Diagram how pulling apart continental crust could create mountains and basins. What are the mountains and

basins called? Answer- When tensional stresses pull crust apart, it breaks into blocks that slide up and drop down along normal faults. The result is alternating mountains and valleys, known as a basin-and-range

3. Why don’t strike slip faults create mountains? Answer-When tensional stresses pull crust apart, it breaks into blocks that slide up and drop down along normal faults. The result is alternating mountains and valleys, known as a basin-and-range

Explanation: I'm really sorry that its a lot but I hope it helps :)

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Two charged particles, with charges q1=q and q2=4q, are located at a distance d= 2.00cm apart on the x axis. A third charged par
Murrr4er [49]

Answer:

X₃₁ = 0.58 m  and  X₃₂ = -1.38 m

Explanation:

For this exercise we use Newton's second law where the force is the Coulomb force

        F₁₃ - F₂₃ = 0

        F₁₃ = F₂₃

Since all charges are of the same sign, forces are repulsive

        F₁₃ = k q₁ q₃ / r₁₃²

        F₂₃ = k q₂ q₃ / r₂₃²

Let's find the distances

         r₁₃ = x₃- 0

         r₂₃ = 2 –x₃

We substitute

      k q q / x₃² = k 4q q / (2-x₃)²

      q² (2 - x₃)² = 4 q² x₃²

        4- 4x₃ + x₃² = 4 x₃²

        5x₃² + 4 x₃ - 4 = 0

We solve the quadratic equation

        x₃ = [-4 ±√(16 - 4 5 (-4)) ] / 2  5

        x₃ = [-4 ± 9.80] 10

       X₃₁ = 0.58 m

       X₃₂ = -1.38 m

For this two distance it is given that the two forces are equal

7 0
3 years ago
What do you mean by kinetic energy and potential energy ?
Verizon [17]

  • Kinetic Energy of an object is the measure of the work an object can do by virtue of its motions..

  • Formula - KE = 1/2 mv^2

  • Where KE is the kinetic energy, m is the body’s mass, and v is the body’s velocity.

  • Potential energy is the stored energy in any object or system by virtue of its position or arrangement of parts..

  • Formula - W = mgh

Where,

. m is the mass in kilograms

. g is the acceleration due to gravity

. h is the height in meters

Hope it helpz~ uh..

4 0
2 years ago
what are the variables in an experiment that tests the distance honey flows at different temperatures? identify the independent
soldier1979 [14.2K]

Answer:

The distance that the honey flowed would be the dependent or outcome variable and the temperature of the honey would be the independent variable.

The dependent variable is what is being measured in an experiment. You can remember it by thinking “it depends on what you’re changing.”

The independent variable in an experiment is what is being changed. You can remember this by thinking “the Independent variable is what I as the scientist change.”

Explanation:

mark me brainliest plz

6 0
3 years ago
Read 2 more answers
1. An asphalt block has a mass of 90 kg and a volume of 0.075 m. Determines the density of the asphalt.
Kisachek [45]

Answer:

1. Density = 1200[kg/m^3]; 2. Volume= 0.005775[m^3], mass= 15.59[kg]

Explanation:

1. We know that the density is defined by the following expression.

Density = \frac{mass}{volume} \\where:\\mass=90[kg]\\volume=0.075[m^{3} ]\\density=\frac{90}{0.075} \\density=1200[\frac{kg}{m^{3} }]

2. First we need to convert the units to meters.

wide = 35[cm] = 35/100 = 0.35[m]

long = 11 [dm] =  11 decimeters = 11/10 = 1.1[m]

Thick = 15[mm] = 15/1000 = 0.015[m]

Now we can find the density using the expression for the density.

density= \frac{mass}{volume} \\where:\\volume = wide*long*thick\\volume=0.35*1.1*0.015 = 0.005775[m^3]\\\\mass= density*volume = 2700*0.005775 = 15.59[kg]

7 0
3 years ago
I'm trying to find the potential energy of a planet using formula G M(sun) x m(planet) / r. I have given G - newton's graviation
ludmilkaskok [199]

Answer:

-5.39\times10^{33} J

Explanation:

Potential energy =

-\frac{GMm}{r}\\=-\frac{6.67\times10^{-11}\times1.99\times10^{30}\times5.97\times10^{24}}{147/1\times10^{9}}\\=-5.39\times10^{33} J

7 0
2 years ago
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