Question

Consider three generic acids: HX , HY , and HZ . The number of H plus and X minus ions in solution is equal to the initial number of HX molecules added to the solution. One quarter of the HZ molecules form H plus and Z minus ions in solution. The other three quarters of the molecules remain as HZ in solution. One half of the HY molecules form H plus and Y minus ions in solution. The other half of the molecules remain as HY in solution. Arrange the acids according to strength.

Answer 1

Answer:

Decreasing order of strength of the the acids :

$HX>HY>HZ$

Explanation:

The strength of an acid is measured by their pH of aqueous solution.

$pH=-\log[H^+]$

$pH\propto \frac{1}{[H^+]}$

• Lower the pH more will be the hydrogen ions and stronger will be the acid.
• Higher the pH less will be the hydrogen ions and weaker will be the acid.

Solution of HX , has equal number of hydrogen ions as a that of its initial molecules o HX.

$[H^+]_x=[HX]$

Solution of HY , molecules of hydrogen ions are half of the molecules of HY.

$[H^+]_y=\frac{1}{2}[HY]$

Solution of HZ , one quarter molecules of hydrogen ions and three quarter  of the molecules of HY.

$[H^+]_z=\frac{1}{4}[HZ]$

$[H^+]_x>[H^+]_y>[H^+]_z$

This means that HX is strongest acid followed by HY and then HZ.

Decreasing order of strength of the the acids :

$HX>HY>HZ$