The molar mass of the gas : 18 x 10⁻³ kg/mol
<h3>Further explanation</h3>Given
An unknown gas has one third the root mean square speed of H2 at 300 K
Required
the molar mass of the gas
Solution
Average velocities of gases can be expressed as root-mean-square (V rms)
T = temperature, Mm = molar mass of the gas particles , kg/mol
R = gas constant 8,314 J / mol K
v rms An unknown gas = 1/3 v rms H₂
v rms H₂ :
V rms of unknown gas =
Answer : We can produce 125.7 g of .
Explanation : The reaction will be
The molecular mass of is 64.1 g/mol
and molecular mass of is 34.1 g/mol
For every mole of we would need twice of
moles, so for every 3 moles of
we need 16 moles of
Now, we can calculate number of moles
2.61 X (3/16) = 0.49 moles
Here, the molecular mass of is 256.8 g
multiplying it with the number of 0.49 moles we get, 256.8 X 0.49 = 125.7 g of .
Hence, 125.7 g of will be produced.