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user100 [1]
3 years ago
5

Using hooke's law find the elastic constant of a spring that stretches 2 cm when 4newton force is applied to it

Physics
1 answer:
Kay [80]3 years ago
3 0

<u>Answer:</u>

2N/cm

<u>Step-by-step explanation:</u>

According to the Hooke's Law, the force required to extend or compress a spring is directly proportional distance you can stretch it, which is represented as:

F=kx

where, F is the force which is stretching or compressing the spring,

k is the spring constant; and

x is the distance the spring is stretched.

Substituting the given values to find the elastic constant  k to get:

F=kx

4=k(2)

k=\frac{4}{2}

k=2

Therefore, the elastic constant is 2 Newton/cm.

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Answer:

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Explanation:

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American Football and Football are different things. The first is what Americans call football, while the other is what Americans call soccer. It is confusing.

6 0
3 years ago
Jessica stretches her arms out 0.60 m from the center of her body while holding a 2.0 kg mass in each hand. She then spins aroun
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Answer:

a.) L = 2.64 kgm^2/s

b.) V = 4.4 m/s

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So,

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L = MVr

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3 years ago
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Answer:

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