Answer:
2 amps
Explanation:
Given data
Power = 460W
voltage= 230V
Required
The amperage/ current of the fuse
Recall P= IV
I= P/V
I= 460/230
I=2 amps
Hence the current of the fuse is 2 amps
To solve this problem it is necessary to apply the concepts related to the principle of superposition and constructive interference, that is to say everything that refers to an overlap of two or more equal frequency waves, which when interfering create a new pattern of waves of greater intensity (amplitude) whose cusp is the antinode.
Mathematically its definition can be given as:

Where
d = Width of the slit
Angle between the beam and the source
m = Order (any integer) which represent the number of repetition of the spectrum, at this case 1 (maximum respect the wavelength)
Since the point of the theta angle for which the diffraction becomes maximum will be when it is worth one then we have to:


Applying the given relation of frequency, speed and wavelength then we will have that the frequency would be:

Here the velocity is equal to the speed of light and the wavelength to the value previously found.


Therefore the smallest microwave frequency for which only the central maximum occurs is 1.5Ghz
Answer:
A factor of 2*4 = 8
Explanation:
F_g = (G*m1*m2)/r^2
where m1 and m2 are the two masses, G is Newton's gravitational constant, and r is the distance between the center of mass of the two objects.
So, if you double m1 and quadruple m2:
m1' = 2*m1
m2' = 4*m2
Then F_g' = (G*m1'*m2')/r^2 = (G*2*m1*4*m2)/r^2 = 8*(G*m1*m2)/r^2 = 8*F_g
Answer:
α = 5 rad / s²
Explanation:
This is a rotational kinematics exercise.
They indicate the initial velocity wo = 10 rad / s
w = w₀ + α t
α =
let's calculate
α =
α = 5 rad / s²
The velocity, the angular relation are the same in all the points of the wheel, the velocities and linear accelerations are the ones that change
a = α r
v = w r