A student throws a water balloon vertically downward from the top of a building. The balloon leaves the thrower's hand with a sp
1 answer:
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here is the question : A student throws a water balloon vertically downward from the top of a building. The balloon leaves the thrower's hand with a speed of 60.0m/s. Air resistance may be ignored,so the water balloon is in free fall after it leaves the throwers hand. a) What is its speed after falling for 2.00s? b) How far does it fall in 2.00s? c) What is the magnitude of its velocity after falling 10.0m?
Answer:
(A) 26 m/s
(B) 32.4 m
(C) v = 15.4 m/s
Explanation:
initial speed (u) = 6.4 m/s
acceleration due to gravity (a) = 9.9 m/s^[2}
time (t) = 2 s
(A) What is its speed after falling for 2.00s?
from the equation of motion v = u + at we can get the speed
v = 6.4 + (9.8 x 2) = 26 m/s
(B) How far does it fall in 2.00s?
from the equation of motion we can get the distance covered
s = (6.4 x 2) + (0.5 x 9.8 x 2 x 2)
s = 12.8 + 19.6 = 32.4 m
c) What is the magnitude of its velocity after falling 10.0m?
from the equation of motion below we can get the velocity
v = 15.4 m/s
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a) The momentum of the ball at the maximum height is zero
b) The momentum of the ball at halfway is 1.06 kg m/s
Explanation:
a)
There is only one force acting on the ball during its motion: the force of gravity, acting downward. As a result, the ball hasa constant acceleration downward (, acceleration of gravity), and therefore it is in free fall motion.
This means that the velocity of the ball is given by the equation:
where
v is the velocity at time t
u = 15 m/s is the initial velocity
As we see from the equation, the term is negative: this means that as the ball goes higher and higher, its velocity decreases. The point of maximum height is reached when the velocity has become zero (after that point, the velocity changes direction and points downward), so when
The momentum of the ball at any point is given by
where m = 0.1 kg is its mass. Therefore, at the maximum height, since , the momentum is also zero:
b)
We can use the following suvat equation to find the maximum height reached by the ball:
where
v = 0 is the velocity at the point of maximum height
u = 15 m/s is the initial velocity
is the acceleration (downward)
s is the vertical displacement (the maximum height)
Solving for s,
This means that the ball is halfway when its height is
We can find the velocity of the ball v' when it is at h' by using again the same equation:
And therefore, the momentum of the ball here is
Learn more about momentum:
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Answer:
1.25x10^-19N
Explanation:see attached file pls
Answer:
A. Object A requires twice the force to stop as Object B.
Explanation:
Inertia can be defined as the tendency of an object or a body to continue in its state of motion or remain at rest unless acted upon by an external force.
Newton's Second Law of Motion states that the acceleration of a physical object is directly proportional to the net force acting on the physical object and inversely proportional to its mass.
Mathematically, it is given by the formula;
<em>Let's assume the following values;</em>
Mass of object B = 10 kg
Mass of object A = 2 * B = 2 * 10 = 20 kg
Acceleration = 5 m/s²
I. To find the force for B;
<em>Force B = 50 Newton</em>
II. To find the force for A;
<em>Force A = 100 Newton</em>
From the calculation, we can deduce that Force A (100 N) is twice or double the value of Force B (50 N).
<em>In conclusion, since object A has twice the mass of object B and both objects are moving at the same speed, object A would require twice the force to stop as Object B.</em>