Answer:
λ = 6 10⁻⁷ m
Explanation:
This problem is a double slit interference spectrum where bright maxima are described by constructive interference.
d sin θ = m λ
Where d is the gap of the slits (d = 0.2 10⁻³ m), m is the maximum interference and λ is the wavelength
We used trigonometry to find the angle
tan θ = y / x
Since the angles in these experiments are very small we use
tan θ = sin θ / cos θ = sin θ
sin θ = y / x
We substitute
d y / x = m λ
λ = d y / m x
In this case the first maximum is m = 1
We substitute
λ = 0.2 10⁻³ 3.6 10⁻³ / (1 1.2)
λ = 6 10⁻⁷ m
The approximation made in this problem is that since the angles are small we approximate the tangent to the sine
Answer:
The top of the ladder go down by 0.15 m.
Explanation:
Here we have right angled triangle.
Hypotenuse = 4.6 m
Bottom angle = 66º
Length from ladder bottom to wall bottom = 4.6 cos66 = 1.87 m
Length from ladder top to wall bottom = 4.6 sin66 = 4.20 m
New length from ladder bottom to wall bottom = 1.87 + 0.31 = 2.18 m
By Pythagoras theorem
New length from ladder top to wall bottom is given by
Distance the top of the ladder go down = 4.20 - 4.05 = 0.15 m
<span>Two characteristics of regular, periodic waveforms are :
</span><span>1) Amplitude - It is the </span><span>the length and width of waves, such as sound
waves, as they move or vibrate. An example would be how
much a radio wave moving back and forth.
</span><span>
2) Frequency - It is the number of waves cycles per unit of time, passing a
point per unit time. It is usually measured in Hertz.</span>
Answer:
Yes
Explanation:
Non uniform acceleration is any acceleration that is not constant.
If you look at the graphs I have drawn in the above picture, the first two graphs shows a uniform acceleration.
The first graph is a positive acceleration, which means that the object is moving faster and faster at a constant rate. The second graph shows a deceleration, or negative acceleration, which means that the object is moving slower and slower at a constant rate.
For velocity- time graphs, acceleration can be seen by its gradient. So if the slope of the graph doesn't change, it has a uniform acceleration.
Graph 3 shows zero acceleration since the object is moving at a constant velocity (or speed). Thus, the object does not acceleration.
Graphs 4-7 shows a non uniform acceleration.
In graph 4, the object has a decreasing acceleration since the gradient of the graph is decreasing. This can be seen by the slope getting gentler and gentler.
Graph 5 shows an increasing deceleration, since the graph is getting steeper and steeper and the velocity is decreasing with time.
Graph 6: increasing acceleration
Graph 7: decreasing deceleration