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pantera1 [17]
2 years ago
11

7. A car stops at a red light. The light turns green

Physics
1 answer:
Readme [11.4K]2 years ago
8 0

Answer:

Graph C

Explanation:

This is the answer because it is the only one that shows the vehicle accelerate to a constant speed before stopping and slowing down.

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A 45-gram object that has a volume of 9 mL has a density of
Elan Coil [88]
The answer : a. 5 g/mL
7 0
3 years ago
Write the equation in slope-intercept form <br> x-2y=4
maxonik [38]

Answer:

y=\frac{1}{2}x-2

Explanation:

Slope-intercept form means we want the y to be by itself in the equation. Every thing we do will be about getting the y alone on the left side of the equation

To start we should move x to the left hand side. We can do this by subtracting x from both sides. That way, there is an x on the right, but not the left.

x-x-2y=4-x

this gives us

-2y=4-x

Great! So now what? Well, the y isn't by itself yet because it still is being multiplied by negative two (-2). In order to move it from the left side to the right side, we have to do the opposite of multiply; divide. So, we will divide both sides by -2

\frac{-2y}{-2} =\frac{4}{-2} -\frac{x}{-2}

-2 divided by -2 is 1, 4 divided by -2 is -2, and -x divided by -2 is \frac{1}{2}x

This gives us the answer:  y=\frac{1}{2}x-2

Tips:

A negative divided by a negative is a positive ex: -4 divided by -2 is positive 2

If you are subtracting by a negative number, you are actually adding by a positive ex: 2-(-2) is actually 2+2

Don't be afraid to have fractions in your equations

Whatever you do to the one side of the equation, you must do it to the other side as well. Multiply the left side by 2? You HAVE TO multiply the right side by two as well. Add 3 to the right side? You HAVE TO add 3 to the left.

For problems like this (and when you have access to the internet), where you need to rewrite an equation, double check your work on desmos, which is an online graphing calculator. Input both the original equation and the equation you rewrote, and if they don't create the same line, you did something wrong.

8 0
3 years ago
Will give brainlist and many points.
romanna [79]

Answer:

They create enormous amounts of sound energy, much like explosion. When an aircraft passes through air, it creates a series of pressure waves just like the waves created by the boat. As the speed of aircraft increases these waves are forced to compress.

3 0
3 years ago
Read 2 more answers
A vector is given by R 2i + j+3k. Find (a) magnitudes of the x, y, and z components; (b) the ma nitude of R; and (c) the angles
Darya [45]

Answer:

given,

R = 2i + j+3k

a) magnitude in x = 2

                          y = 1

                          z = 3

b) magnitude of R

R = \sqrt{2^2+1^2+3^2}

R = 3.74 units

c) angle between the R and  the x, y, and z axes.

cos \theta_x=\dfrac{2}{3.74}

θ x = 57.72°

cos \theta_y=\dfrac{1}{3.74}

θ y = 74.51°

cos \theta_z=\dfrac{3}{3.74}

θ z = 36.68°

4 0
3 years ago
A very long, solid insulating cylinder has radius R; bored along its entire length is a cylindrical hole with radius a. The axis
lawyer [7]

Answer:

The value of the electric field is E_{net} = \dfrac{r \textbf{b}}{2\epsilon_{0}}

Explanation:

We know that the electric field inside a solid cylinder at a distance \textbf{r} from the centre is given by

E = \dfrac{\rho \textbf{r}}{2 \epsilon_{0}}

Let's consider the cross-section of the cylinder as shown in the figure. Let `O' be the centre of the long solid insulating cylinder having radius 'R'. Also consider that O' be the cetre of the hole of radius 'a' situated at a distance 'b' from 'O'. Given, the volume charge density of the material is 'r'. So, the volume charge density inside the hole will be '-r'. Let's consider 'P' be any arbitrary point inside the hole situated at a distance 's' from O'.

So, the electric field 'E_{O}' due to the long cylinder at point 'P' is given by

E_{O} = \dfrac{r \textbf{c}}{2 \epsilon_{0}}

and the electric field 'E_{O'}'due to the hole at point 'P' is given by

E_{O'} = \dfrac{\rho \textbf{s}}{2 \epsilon_{0}}

So the net electric field (E_{net}) inside the hole is given by

E_{net} = E_{O} - E_{O'} = \dfrac{r}{2\epsilon_{0}}(\textbf{c - s}) = \dfrac{r \textbf{b}}{2\epsilon_{0}}

5 0
4 years ago
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