Question

Y=-4(x-4)^2+8 in standard form

Answer 1

Answer:

y = $-4x^{2} +32x-56$

Step-by-step explanation:

$y=-4(x-4)^{2} +8$

$y=-4((x-4) (x-4)) +8$

$y=-4(x^{2} -8x+16)+8$

$y= -4x^{2} +32x-64+8$

$y=-4x^{2} +32x-56$