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Answer:
Gravity controls the movement of the planets around the sun, holds together stars grouped in galaxies, and galaxies grouped in clusters. The Universal Law of Gravitation depends on two things. First it depends on mass of each object and the second factor is the distance between two objects. If the mass of one object is Larger, the gravitational pull towards it will be larger and the smaller distance, the larger the gravitational pull will be between the objects. Therefore the Larger planets have more moon and the inner planets have less.
Explanation:
Answer:
n=0.03928 moles
Moles of oxygen do the lungs contain at the end of an inflation are 0.03928 moles
Explanation:
The amount of oxygen which lung can have is 20% of 5 L which is the capacity of lungs
Volume of oxygen in lungs =V=5*20%= 1 L=
Temperature=T=
Pressure at sea level = P= 1 atm=
R is universal Gas Constant =8.314 J/mol.K
Formula:

Moles of oxygen do the lungs contain at the end of an inflation are 0.03928 moles
<span>In order to answer this question you need to know the specific heat of aluminum and water.
The source below says 0.900 J/g K and 4.186 J/g K respectively.
Let T be the final temperature to be found:
(0.900 J/g K) x (270 g) x (T - (-20))K = (243T + 4860) J gained by the Al
(4.186 J/g K) x (500 g) x (85 - T)K = (177905 - 2093T ) J lost by the coffee
Set the two expressions for heat gained/lost equal to each other:
243T + 4860 = 177905 - 2093T
Solve for T algebraically:
T = 74.1 °C</span>
Answer:
Explanation:
Stiffness of spring k equal to 4 lb/ft.
Unstretched length of the spring L is equal to 0.5 feet.
Weight of the collar W is 15lb
Radius of curvature of curve guide is 1 feet
length of vertical rod is 1.5 feet
Initial speed of collar when released from rest at A is 0 feet per seconds
use the energy conservation equation

Estimate the potential energy , component as position B as below

Estimate the kinetic energy , component as position A as below

Estimate the kinetic energy , component as position B as below

Substitute 20.5lb- ft for 
0.5lb-ft for 
0lb -ft for 


= 16.05ft/sec