Answer: The concentration of
in the final solution is 0.006688 M and number of moles are 0.00006688
Explanation:
According to the neutralization law,

where,
= molarity of stock solution = 6.847 M
= volume of stock solution = 25.00 ml
= molarity of ist dilute solution = ?
= volume of first dilute solution = 100.0 ml


2) on second dilution;


3) on third dilution


4) on fourth dilution


5) on fifth dilution


Thus the concentration of
in the final solution is 0.006688 M
moles of
= 
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2:2 is the answer to your question