Can someone help<br> Me out pls if your good at chemistry

Increased irrigation demands: decrease the rate of transpiration increase the rate of surface water evaporation change the amoun

drek231 [11]

Answer: Increase the rate of surface water evaporation

Irrigation is a process, in which the crops are supplied with water, to ensure their proper growth. Increased in the irrigation supply can be because of the environmental conditions like hot summer season or may be because of the type of soil is semi arid or arid means the soil does not retains moisture efficiently. This will result in increase in the rate of evaporation of the surface water.

7 0

3 years ago

The combustion of ethene in the presence of excess oxygen yields carbon dioxide and water: c2h4 (g) + 3o2 (g) → 2co2 (g) + 2h2o

meriva

Answer:

$\boxed{-267.5}$

Explanation:

You can calculate the entropy change of a reaction by using the standard molar entropies of reactants and products.

The formula is

$\Delta_{r} S^{\circ} = \sum_n {nS_{\text{products}}^{\circ} - \sum_{m} {mS_{\text{reactants}}^{\circ}}}$

The equation for the reaction is

C₂H₄(g) + 3O₂(g) ⟶ 2CO₂(g) + 2H₂O(ℓ)

ΔS°/J·K⁻¹mol⁻¹ 219.5 205.0 213.6 69.9

$\Delta_{r} S^{\circ} = (2\times213.6 + 2\times69.9) - (1\times219.5 + 3\times205.0)\\\\= 567.0 - 834.5 = \boxed{-267.5 \text{ J}\cdot\text{K}^{-1} \text{mol}^{-1}}$

3 0

3 years ago

Which of the following best describes where cellular respiration occurs?

Illusion [34]

Answer:

In every body cell

Explanation:

4 0

3 years ago

Read 2 more answers

Rank the elements according to highest ionization energy:<br><br> Be, C, O, Ne, B, Li, F, N

aleksklad [387]

Given:
Be - Beryllium   -   9,3227
C   - Carbon - 11,2603
O   - Oxygen - 13,6181
Ne - Neon - 21,5645
B   - Boron -   8,298
Li - Lithium -   5,3917
F   - Fluorine - 17,4228
N   - Nitrogen - 14,5341

Arranged from highest ionization energy to lowest ionization energy.

Ne ; F ; N ; O ; C ; Be ; B ; Li

5 0

3 years ago

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The reaction of nitrogen gas and oxygen gas to form nitrogen monoxide gas is shown below. If the measured concentrations of all

Anettt [7]

Answer:

The forward reaction is occurring at a faster rate than the reverse reaction.

Explanation:

Reaction quotient (Q) of the given reaction is -

$Q=\frac{[NO]^{2}}{[N_{2}][O_{2}]}$

where [NO], $[N_{2}]$ and $[O_{2}]$ represents concentrations of respective species at a certain time.

Here $[N_{2}]$ = 0.80 M, $[O_{2}]$ = 0.050 M and [NO] = 0.10 M

So, $Q=\frac{(0.10)^{2}}{(0.80)\times (0.050)}=2$

Hence $Q> K$

It means that forward reaction is faster than reverse reaction at that point. Because then only concentration of NO is higher than concentrations of $[N_{2}]$ and $[O_{2}]$ which makes Q higher than K.

4 0

2 years ago

Can someone help Me out pls if your good at chemistry