Both don’t have units beacuse they are ratios
Answer:
The appropriate solution is "2.78 mm".
Explanation:
Given:
![\lambda = 720 \ nm](https://tex.z-dn.net/?f=%5Clambda%20%3D%20720%20%5C%20nm)
or,
![= 720\times 10^{-9} \ m](https://tex.z-dn.net/?f=%3D%20720%5Ctimes%2010%5E%7B-9%7D%20%5C%20m)
![D=0.85 \ m](https://tex.z-dn.net/?f=D%3D0.85%20%5C%20m)
![d = 0.22 \ mm](https://tex.z-dn.net/?f=d%20%3D%200.22%20%5C%20mm)
or,
![=0.22 \times 10^{-3} \ m](https://tex.z-dn.net/?f=%3D0.22%20%5Ctimes%2010%5E%7B-3%7D%20%5C%20m)
As we know,
Fringe width is:
⇒ ![\beta=\frac{\lambda D}{d}](https://tex.z-dn.net/?f=%5Cbeta%3D%5Cfrac%7B%5Clambda%20D%7D%7Bd%7D)
hence,
Separation between second and third bright fringes will be:
⇒ ![\theta=\beta=\frac{\lambda D}{d}](https://tex.z-dn.net/?f=%5Ctheta%3D%5Cbeta%3D%5Cfrac%7B%5Clambda%20D%7D%7Bd%7D)
![=\frac{720\times 10^{-9}\times 0.85}{0.22\times 10^{-3}}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B720%5Ctimes%2010%5E%7B-9%7D%5Ctimes%200.85%7D%7B0.22%5Ctimes%2010%5E%7B-3%7D%7D)
![=2.78\times 10^{-3} \ m](https://tex.z-dn.net/?f=%3D2.78%5Ctimes%2010%5E%7B-3%7D%20%5C%20m)
or,
![=2.78 \ mm](https://tex.z-dn.net/?f=%3D2.78%20%5C%20mm)
Answer:
The answer is 39.
Explanation:
The atomic number refers to the number of protons and the atomic mass is the sum of the protons and neutrons. So, you would just do 70 - 31 and that gets you 39.
Explanation:
It is given that,
Mass of the soccer ball, m = 0.425 kg
Speed of the ball, u = 15 m/s
Angle with horizontal, ![\theta=33^{\circ}](https://tex.z-dn.net/?f=%5Ctheta%3D33%5E%7B%5Ccirc%7D)
Time for which the player's foot is in contact with it, ![\Delta t = 5.1\times 10^{-2}\ s](https://tex.z-dn.net/?f=%5CDelta%20t%20%3D%205.1%5Ctimes%2010%5E%7B-2%7D%5C%20s)
Part A,
The x component of the soccer ball's change in momentum is given by :
![\Delta p_x=mv\ cos\theta](https://tex.z-dn.net/?f=%5CDelta%20p_x%3Dmv%5C%20cos%5Ctheta)
![\Delta p_x=0.425\times 15\ cos(33)](https://tex.z-dn.net/?f=%5CDelta%20p_x%3D0.425%5Ctimes%2015%5C%20cos%2833%29)
![p_x=5.34\ kg-m/s](https://tex.z-dn.net/?f=p_x%3D5.34%5C%20kg-m%2Fs)
The y component of the soccer ball's change in momentum is given by :
![\Delta p_y=mv\ sin\theta](https://tex.z-dn.net/?f=%5CDelta%20p_y%3Dmv%5C%20sin%5Ctheta)
![\Delta p_y=0.425\times 15\ sin(33)](https://tex.z-dn.net/?f=%5CDelta%20p_y%3D0.425%5Ctimes%2015%5C%20sin%2833%29)
![p_y=3.47\ kg-m/s](https://tex.z-dn.net/?f=p_y%3D3.47%5C%20kg-m%2Fs)
Hence, this is the required solution.
Answer:
A physical change involves a change in physical properties. Examples of physical properties include melting, transition to a gas, change of strength, change of durability, changes to crystal form, textural change, shape, size, color, volume and density.