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Ghella [55]
1 year ago
6

You are operating a powerboat at night. Your red sidelight must be visible to boats approaching from which direction(s)

Physics
1 answer:
Dmitriy789 [7]1 year ago
4 0

The answer is the red sidelight on a powerboat should be visible from the front and from the left (port side).

What are Sidelights?

  • There is various combinations of lights that must be used on a boat when it is dark, and these are:
  • Sidelights: These lights are called combination lights and are red and green. The red sidelight must be visible from the port side and the green light indicates the right side (the starboard).
  • Stern light: The stern light is seen at the back end of the vessel.
  • Masthead Light: The masthead light is a white light that shines forwards and on all sides of the vessel. All powered vessels must use this light.
  • All-Round white light: This light is the major light that is used to join the masthead light and the stern light. This single light is visible to all vessels from all directions.
  • Thus, as a rule for a boat rider, he should show the vision of red light and it should be visible from the front and from the left (port side).

To learn more about Sidelights visit:

brainly.com/question/28205057

#SPJ4

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active and passive secruity measures are employed to identify, detect, classify and analyze possible threats inside of which zon
Juli2301 [7.4K]

Answer:

Assessment zone

Explanation:

It is the assessment zone in various security zones where active and passive security measures are employed to identify, detect, classify and analyze possible threats inside the assessment zones.

8 0
3 years ago
A 1250 kg car, driving 7.39 m/s, runs into the back of a stationary 5380 kg truck. After the collision, the truck moves forward
Leno4ka [110]

Explanation:

Given that,

Mass of the car, m₁ = 1250 kg

Initial speed of the car, u₁ = 7.39 m/s

Mass of the truck, m₂ = 5380 kg

It is stationary, u₂ = 0

Final speed of the truck, v₂ = 2.3 m/s

Let v₁ is the final velocity of the car. Using the conservation of momentum as :

m_1u_1+m_2u_2=m_1v_1+m_2v_2

1250\times 7.39+5380\times 0=1250\times v_1+5380\times 2.3

v_1=-2.5\ m/s

So, the final velocity of the car is 2.5 m/s but in opposite direction. Hence, this is the required solution.

3 0
3 years ago
7 the density of the american white oak tree is 752 kilograms per cubic meter. if the trunk of an american white oak tree has a
alexdok [17]

First, we determine the volume of the trunk by finding first the radius from the circumference through the equation,

<span>                                                            C = 2πr</span>

<span>                                                            r = C/2π</span>

Substituting the known values,

<span>                                                            r = 4.5/2π = 0.716 m</span>

Then, we calculate for the volume through the equation,

<span>                                                            V = πr2h</span>

<span>                                                V = π(0.716 m)2(8m) = 12.9 m3</span>

Multiplying the calculated value to the density will give the mass as,

<span>                                                Mass = (12.9 m3)(752 kg/m3) = <span>9699.36 kg</span></span>

3 0
3 years ago
Measure the mass of a coin using a triple beam balance.
Mariana [72]

Explanation:

The triple beam balance is used to measure masses very precisely; the reading error is 0.05g

7 0
3 years ago
Two long, straight wires are parallel and 26 cm apart.
mezya [45]

Answer: 2.49×10^-3 N/m

Explanation: The force per unit length that two wires exerts on each other is defined by the formula below

F/L = (u×i1×i2) / (2πr)

Where F/L = force per meter

u = permeability of free space = 1.256×10^-6 mkg/s^2A^2

i1 = current on first wire = 57A

i2 = current on second wire = 57 A

r = distance between both wires = 26cm = 0.26m

By substituting the parameters, we have that

Force per meter = (1.256×10^-6×57×57)/ 2×3.142 ×0.26

= 4080.744×10^-6/ 1.634

= 4.080×10^-3 / 1.634

= 2.49×10^-3 N/m

5 0
3 years ago
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