Question

Water flows from one reservoir to another a height, 41 m below. A turbine (η=0.77) generates power from this flow. 1 m3/s passes through the turbine. If 12 m head loss occurs between the two reservoirs, determine the actual (i.e. useable) power generated by the turbine (in kW).

Answer 1

Complete Question

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Answer:

The value is $P = 294594.3 \ W$

Explanation:

From the question we are told that

   The height is  $h = 41 \ m$

   The efficiency of the turbine is $\eta = 0.77$

   The flow rate is $\r V = 1 m^3 / s$

    The head loss is  g =  2 m

Generally the head gain by the turbine is mathematically represented as      

        $H = h - d$

=>     $H = 41 - 2$

=>     $H = 39 \ m$

Generally the actual power generated by the turbine is mathematically represented as

          $P = \eta *\gamma * \r V * H$

Here $\gamma$ is the specific density of water with value

        $\gamma = 9810 N/m^3$

So

       $P =0.77 *9810 * 1 * 39$

       $P = 294594.3 \ W$