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lesantik [10]
3 years ago
5

Water flows from one reservoir to another a height, 41 m below. A turbine (η=0.77) generates power from this flow. 1 m3/s passes

through the turbine. If 12 m head loss occurs between the two reservoirs, determine the actual (i.e. useable) power generated by the turbine (in kW).

Physics
1 answer:
morpeh [17]3 years ago
5 0

Complete Question

A diagram representing this question is shown on the first uploaded image

Answer:

The value is P = 294594.3 \ W

Explanation:

From the question we are told that

   The height is  h  =  41 \  m

   The efficiency of the turbine is \eta =  0.77

   The flow rate is \r  V  = 1 m^3 / s

    The head loss is  g =  2 m

Generally the head gain by the turbine is mathematically represented as      

        H  =  h -  d

=>     H  =  41 - 2

=>     H  =  39 \  m

Generally the actual power generated by the turbine is mathematically represented as

          P =  \eta  *\gamma *    \r V * H

Here \gamma is the specific density of water with value

        \gamma   =  9810 N/m^3

So

       P =0.77  *9810 *   1 *  39

       P = 294594.3 \ W

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