Answer:
1.) Displacement = 32.08m
2.) Velocity = 55km/h
3.) Acceleration = 94.29 km/h^2
Explanation:
Given that the train takes 35 minutes to cover the distance between the two towns. The train's average speed is 55 kilometers per hour. That is,
Time t = 35 minute
Convert it to hours by dividing it by 60
35/60 = 7/12 hours
Speed = 55 km/h
The displacement of the car is:
Displacement = 55 × 7/12 = 32.08 m
The velocity of the car will be 55 km/h
The acceleration of the car will be:
Acceleration = velocity/time
Substitute velocity and time into the formula
Acceleration = 55 ÷ 7/12
Acceleration = 94.29 km/h^2
Answer:
initial speed is 13.36 m/s
Explanation:
given data
mass = 2 kg
velocity = 10 m/s
distance = 20 m
friction= 0.2
to find out
initial speed
solution
we find first friction force that is
friction force = friction ×mass×g ...........1
put here value
friction force = 0.2 × 2 × 9.81
friction force = 3.924 N
here a will be -ve due to friction
- friction force = mass × acceleration
acceleration = - friction force / mass
acceleration = - 3.924 / 2
acceleration = - 1.962 m/s²
and we know velocity formula that is
V² = V(i)² + 2as
put here value
10² = V(i)² + 2(-1.962)(20)
V(i) = 13.36
so initial speed is 13.36 m/s
Qs 1: m = 1/2*KE*V^2
qs 2: 6,223.39 kg
Use the Ideal Gas Law to the air in the tire :
( P ) ( V ) = ( n ) ( R ) ( T )
n = ( P ) ( V ) / ( R ) ( T )
P = P gauge + P baro = 31.2 psig + 14.8 psia = 46 psia
P = ( 46 psia ) ( 1 atm / 14.696 psia ) = 3.13 atm
n = ( P ) ( V ) / ( R ) ( T )
n = ( 3.13 atm ) ( 4.6 L ) / ( 0.08206 atm - L / mol - K ) ( 26.0 + 273.2 K )
n = 0.5864 moles
m = ( n ) ( M )
m = ( 0.5864 mol ) ( 28.96 g/ mol ) = 16.98 g
