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pychu [463]
4 years ago
12

What the charges of the nucleus

Physics
1 answer:
saw5 [17]4 years ago
4 0
Protons are positive, electrons are negative, and neutrons are neutral. In the nucleus, there are protons and neutrons, so the charge of a nucleus is positive.
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Tech A says that a relay is a one-way electrical check valve used in alternators to change AC into DC. Tech B says that a relay
Setler [38]

Answer:

The correct answer is from Tech B.

Explanation:

The relay is an electromagnetic device, which is stimulated by a very weak electrical current to open or close a circuit.  It functions as a switch controlled by an electrical circuit in which, by means of a coil and an electromagnet, a sequence of one or several contactors is activated that allow to open or close other electrical circuits independent of the one that controls it.

Have a nice day!

7 0
3 years ago
How far does Andre have to push a box to do 430 J of work, if he applies a force of 15 Newtons
kap26 [50]

Answer:

28.7m

Explanation:

Given parameters;

Work done  = 430J

Force applied  = 15N

Unknown:

Distance moved  = ?

Solution:

Work done is the force applied to move a body through a certain distance.

     Work done  = Force x distance

So;

         430  = 15 x distance

      Distance  = 28.7m

3 0
3 years ago
What organ is muscular and houses the develop fetus?
White raven [17]
<span>Uterus (structure) ...</span>
5 0
4 years ago
Read 2 more answers
I don’t know what to do
zavuch27 [327]

Answer:

So increasing the voltage increases the charge in direct proportion to the voltage. If the voltage exceeds the capacitors rated voltage, the capacitor may fail due to breakdown of the dielectric between the two plates that make up the capacitor.

Explanation:

A option.

7 0
3 years ago
A steel sphere sits on top of an aluminum ring. The steel sphere (a= 1.1 x 10^-5/degrees celsius) has a diameter of 4.000 cm at
Mars2501 [29]

Answer:

C

Explanation:

To solve this question, we will need to develop an expression that relates the diameter 'd', at temperature T equals the original diameter d₀ (at 0 degrees) plus the change in diameter from the temperature increase ( ΔT = T):

d = d₀ + d₀αT

for the sphere, we were given

D₀ = 4.000 cm

α = 1.1 x 10⁻⁵/degrees celsius

we have D = 4 + (4x(1.1 x 10⁻⁵)T = 4 + (4.4x10⁻⁵)T             EQN 1

Similarly for the Aluminium ring we have

we were given

d₀ = 3.994 cm

α = 2.4 x 10⁻⁵/degrees celsius

we have d = 3.994 + (3.994x(2.4 x 10⁻⁵)T = 3.994 + (9.58x10⁻⁵)T       EQN 2

Since @ the temperature T at which the sphere fall through the ring, d=D

Eqn 1 = Eqn 2

4 + (4.4x10⁻⁵)T =3.994 + (9.58x10⁻⁵)T, collect like terms

0.006=5.18x10⁻⁵T

T=115.7K

4 0
3 years ago
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