Answer:
If I'm not mistaken the horizontal rows are periods and the vertical columns are familes.
Explanation:
Answer:
'Oxidation states have changed.'
Explanation:
Redox Reactions can be identifiable by a change in oxidation number/states of two of the atoms in the reaction. Any reaction in which no oxidation numbers/state change is not a redox reaction.
Chemical Bonding, my dude.
Answer:
ok
Explanation:
Element %composition Mol. mass No. of C atoms Simplest Rounding
ratio off
C 82.76 12 6.89 1× 2 2
H 17.24 1 17.24 2.5× 2 5
Number of carbon atoms present =
12
82.76
=6.89
Number of hydrogen atoms present =
1
17.24
=17.24
simplest ratio =
6.89
6.89
=1
simplest ratio =
6.89
17.24
=2.5
∴ Empirical fromula is C
2
H
5
Empirical formula mass= 2×12+5 = 29
∴ V.D. = 29
Mol. mass = 2 × V.D.
=58
n=
Empiricalformulamass
Molecularmass
=
29
58
=2
∴ Molecular formula = C
4
H
10
<em>pls mark me as braillant</em>
empirical formula is the simplest ratio of whole numbers of components making up a compound
molecular formula is the actual number of components making up the compound
there can be many compounds having the same empirical formula
given options
1. C₂H₆ and C₄H₁₂
ratio of C to H in C₂H₆ - 2:6 --> 1:3
C₄H₁₂ - 4:12 --> 1:3
the simplified ratios for both are same
therefore both have same empirical formulas
2. C₃H₆O₃ and C₂H₄O₂
ratio of C to H to O in C₃H₆O₃ - 3:6:3 --> 1:2:1
C₂H₄O₂ - 2:4:2 --> 1:2:1
both have same empirical formulas
3. C₃H₈O and CH₂O
ratio of C to H to O in C₃H₈O - 3:8:1
CH₂O - 1:2:1
the 2 ratios of atoms are different which means they have different empirical formulas
4. C₂H₈ and CH₄
ratio of C to H in C₂H₈ - 2:8 --> 1:4
CH₄ -- 1:4
2 ratios are same so same empirical formula
correct answer is 3. C₃H₈O and CH₂O they do not share the same empirical formula