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3 years ago

What is the frequency of a wave that has a speed of 8 m/s and a wavelength of 2.0 m?

Physics

2 answers:

dexar [7]3 years ago

6 0

F = 8m/s / 2m = 4 Hz
easy as that

Stells [14]3 years ago

4 0

Answer:

Frequency of the wave, f = 4 Hz

Explanation:

It is given that,

Speed of the wave, v = 8 m/s

Wavelength of the wave, λ = 2 m

We have to find the frequency of the wave. The relationship between the frequency, wavelength and the speed of the wave is given by :

$v=f\times \lambda$

$f=\dfrac{v}{\lambda}$

$f=\dfrac{8\ m/s}{2\ m}$

f = 4 Hz or 4 s⁻¹

So, the frequency of the wave is 4 Hz. Hence, the correct option is (c) " 4 Hz".

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if the net force of an object is in a positive direction what will the direction of the resulting acceleration be

myrzilka [38]

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Hope this helps!

3 0

3 years ago

Two laws are described below:

sesenic [268]

B, Both law a and b because they both in science terms are scientific laws

4 0

3 years ago

A rocket is launched from rest and moves in a straight line at 30.0 degrees above the horizontal with an acceleration of 35.0 m/

klemol [59]

Answer:

t = 123.59s

Explanation:

For the launch pad section:

Vf = Vo + a*t where Vo=0.

Vf = 35*25 = 875m/s

The distance traveled during the launch:

$d = Vo*t+\frac{a*t^2}{2} = 0+\frac{35*25^2}{2} = 10937.5m$

Now the projectile motion, we know that its initial speed is the speed calculated previously and the initial height is the y-component of the previously calculated distance.

$\Delta Y = Vo*sin(30)*t - \frac{g*t^2}{2}$

$-d*sin(30) = Vo*sin(30)*t - \frac{g*t^2}{2}$ where d= 10937.5m; Vo=875m/s.

Solving for t:

t1 = -11.093s t2 = 98.59s

So, the total time of flight will be:

$t_{total} = t_{launch}+t_{projectile}=25+98.59 = 123.59s$

6 0

3 years ago

8. A car moving at 35 m/s has 675 joules of KE. What is the mass of the car?

andreyandreev [35.5K]

Kinetic energy is the energy possessed by a body in motion while potential energy is the energy of a body at rest.
Kinetic energy is given by E=1/2MV² where M is the mass of the body while V is the velocity of the body.
To get mass we can use the formula M= 2 Ek/V² (Making M the subject)
hence mass = (2 ×675)÷35²
= 1.102 kg

6 0

3 years ago

The voltage across the terminals of a 9.0 v battery is 8.5 v when the battery is connected to a 60 ω load. part a what is the ba

snow_lady [41]

Refer to the diagram shown below.

i = the current in the circuit., A
R₁ = the internal resistance of the battery, Ω
R₂ = the resistance of the 60 W load, Ω

Because the resistance across the battery is 8.5 V instead of 9.0 V, therefore
(R₁ )(i A) = 9 - 8.5 = (0.5 V)
R₁*i = 0.5 (10

Also,
R₂*i = 9.5 (2)

Because the power dissipated by R₂ is 60 W, therefore
i²R₂ = 60
From (2), obtain
i*9.5 = 60
i = 6.3158 A

From (1), obtain
6.3158*R₁ = 0.5
R₁ = 0.5/6.3158 = 0.0792 Ω = 0.08 Ω (nearest hundredth)

Answer: 0.08 Ω

3 0

3 years ago

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