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kodGreya [7K]
3 years ago
13

A large balloon has a volume of 2.5 L at a temp of 0 degrees C. what is the new volume of the balloon at a constant pressure whe

n the temp rises to 120 degrees C?
Chemistry
1 answer:
gladu [14]3 years ago
3 0

Answer:

2.5

Explanation:

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Consider the reaction of 35.0 g of iron as follows:
77julia77 [94]

Explanation:

4Fe + 3O2 --> 2Fe2O3

Mass of  iron = 35g

<em>How many moles of iron react?</em>

The relationship between mass and moles is given as;

Moles = mass /  Molar mass

Molar mass of iron = 56g/mol

Number of moles = 35 / 56 = 0.625 mol

<em>How many moles of oxygen molecules must react?</em>

From the equation of the reaction;

4 mol of Fe reacts with 3 mol of Oxygen molecule

0.625 mol would react with x mol?

4 = 3

0.625 = x

x = 0.625 * 3 / 4 = 0.46875 mol

<em>How many moles of product form?</em>

From the equation of the reaction;

4 mol of Fe reacts to form 2 mol of Fe2O3

0.625 mol would form x mol of Fe2O3

4 = 2

0.625 = x

x = 0.625 * 2 / 4 = 0.3125 mol

<em>What mass of product forms?</em>

Moles = mass /  Molar mass

Mass = Molar mass * Moles = 159.69 g/mol * 0.3125 mol = 49.9g

8 0
3 years ago
A 1.00 l solution contains 3.50×10-4 m cu(no3)2 and 1.75×10-3 m ethylenediamine (en). the kf for cu(en)22+ is 1.00×1020. what is
Alik [6]
<span>Answer: A 1.00 L solution containing 3.00x10^-4 M Cu(NO3)2 and 2.40x10^-3 M ethylenediamine (en). contains 0.000300 moles of Cu(NO3)2 and 0.00240 moles of ethylenediamine by the formula Cu(en)2^2+ 0.000300 moles of Cu(NO3)2 reacts with twice as many moles of en = 0.000600 mol of en so, 0.00240 moles of ethylenediamine - 0.000600 mol of en reacted = 0.00180 mol en remains by the formula Cu(en)2^2+ 0.000300 moles of Cu(NO3)2 reacts to form an equal 0.000300 moles of Cu(en)2^2+ Kf for Cu(en)2^2+ is 1x10^20. so 1 Cu+2 & 2 en --> Cu(en)2^2+ Kf = [Cu(en)2^2+] / [Cu+2] [en]^2 1x10^20. = [0.000300] / [Cu+2] [0.00180 ]^2 [Cu+2] = [0.000300] / (1x10^20) (3.24 e-6) Cu+2 = 9.26 e-19 Molar since your Kf has only 1 sig fig, you might be expected to round that off to 9 X 10^-19 Molar Cu+2</span>
4 0
3 years ago
The quantities 1 mol and 22.4 L can be used in conversion factors that change moles to volume and volume to moles at STP.
Luden [163]
True. Bc 1 mol and 22.4 L=23.4
6 0
3 years ago
Read 2 more answers
a sample of solid is decomposed and found to contain 6.52g of potassium, 4.34 g of chromium and 5.34 of oxygen, what is the empi
Fynjy0 [20]

Answer:

K₂CrO₅

Explanation:

The empirical formula is the simplest formula of a compound. To find the empirical formula, we follow the procedure below:

Elements                         Potassium                 Chromium         Oxygen

Mass                                  6.52                             4.34                  5.34

Molar mass                          39                               60                      16

Number of moles             6.52/39                     4.34/60             5.34/16

                                             0.167                          0.072              0.333

Divide through by

the smallest                      0.167/0.072             0.072/0.072          0.333/0.072

                                            2.3                               1                                4.6

                                             2                                 1                                  5

Empirical formula K₂CrO₅

5 0
3 years ago
6. Which describes particles or electromagnetic radiation emitted from the nucleus during
leonid [27]

Answer:

A harmless nuclear fallout

Explanation:

just did this

6 0
2 years ago
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