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damaskus [11]
3 years ago
9

What important characteristics of planets and moon are studied by astronomers?

Physics
1 answer:
kondor19780726 [428]3 years ago
5 0

mass density orbit time temperature surface conditions

distyance from sun

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What is the weight of a ring tailed lemur that has a mass of 10 kg? Use w = mg (g = -9.8 m/s^2)
marusya05 [52]

m = 10 kg

g = -9.8 m/s2

w = m * g

w= -9.8 * 10

w= -98 N

4 0
3 years ago
Air has a density of 1.3 kg/m³. Calculate the mass of 36 m³ of air in kilograms. Give your answer to 1 decimal place.
vredina [299]

Answer:

46.8 kg

Explanation:

Mass = (density)(volume)

= (1.3)(36)

<u>M</u><u>a</u><u>s</u><u>s</u><u> </u><u>=</u><u> </u><u>4</u><u>6</u><u>.</u><u>8</u><u> </u><u>k</u><u>g</u>

3 0
3 years ago
When the formula m*g=F-Fg is used?​
valina [46]

The formula (ma = F - Fg) is used to determine the net upward force acting on a body.

<h3>What is net upward force acting on a body?</h3>

The net upward force acting on a body is the resultant or sum of all the upward forces acting on a body at a given time.

ma = F - Fg

where;

  • F is the applied force
  • Fg is the force of gravity
  • ma is the resultant force

Thus, the formula (ma = F - Fg) is used to determine the net upward force acting on a body.

Learn more about force here: brainly.com/question/12970081

#SPJ1

3 0
2 years ago
A 40 kg dog is sitting on top of a hillside and has a potential energy of 1,568 J. What is the height of the hillside?
beks73 [17]
Potential Energy=M x G x  H
1,568=40 x 10 x H 
Now we isolate the H 
h=3.92m 

8 0
3 years ago
The radius of the aorta is about 1 cm and the blood flowing through it has a speed of about 30 !" ! . Calculate the average spee
Julli [10]

Answer:

The average speed of the blood in the capillaries is 0.047 cm/s.

Note: The question is incomplete. The complete question is as follows:

The radius of the aorta is about 1 cm and the blood flowing through it has a speed of about 30 cm/s. Calculate the average speed of the blood in the capillaries given the total cross section of all the capillaries is about 2000 cm².

Explanation:

From the given values:

radius of the aorta, r₁ = 1 cm

speed of blood, v₁ = 30 cm/s

Area of the aorta, A₁ = πr₁² where π = 3.142

Area of aorta = 3.142 × (1)² = 3.142 cm²

Area of the capillaries, A₂ = 2000 cm²

let the average speed of the blood in the capillaries = v₂

From the continuity equation of fluid flow, the product of cross-sectional area of the pipe and the fluid speed at any point along the pipe is always constant. In formula, A₁v₁ = A₂v₂

Using the continuity equation, the average the average speed of the blood in the capillaries can be calculated thus:

A₁v₁ = A₂v₂

v₂ = (A₁v₁) / (A₂)

v₂ = (3.142 x 30) / (2000)

v₂ = 0.047 cm/s

Therefore, the average speed of the blood in the capillaries is 0.047 cm/s.

4 0
3 years ago
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