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lawyer [7]
3 years ago
14

Why does magma rise from depth to the surface of the earth?

Physics
2 answers:
Viefleur [7K]3 years ago
6 0

Answer

Magma is less dense compared to the surrounding rock.

the overlying rock creates pressure which forces the magma to be directed upward.

Explanation:

at high temperatures the magma is liquid form with the high energy which causes the formation of bonds and the pressure build up creates the increase  channeling of the liquid.as the temperature decreases the magma moves into the surface

grigory [225]3 years ago
4 0

Explanation:

Any rock will melt once it reaches a high enough temperature. This liquid rock is known as magma when it is beneath the crust of the Earth. If it bubbles to the surface and pushes its way out, it is known as lava. This happens most often in a volcano.

Magma rising from the depth occurs when hot mantle rock rises to shallower depths in the Earth because it is less dense than surrounding rock and because the weight of the overlying rock creates pressure that squeezes magma upward.

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State the principle of floatation​
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Explanation:

<em><u>Principle of Floatation</u></em>

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7 0
2 years ago
You run away from a plane mirror at 1.80 m/s. At what speed does your image move away from you?
Vlad [161]

Answer:

3.60m/s

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4 0
3 years ago
Calculate the period of a spring if it has a mass of 5 kg and a spring constant of 6 N/m
otez555 [7]

Answer: The period of a spring if it has a mass of 5 kg and a spring constant of 6 N/m is 5.73 sec.

Explanation:

Given: Mass = 5 kg

Spring constant = 6 N/m

Formula used to calculate period is as follows.

T = 2 \pi \sqrt\frac{m}{k}

where,

T = period

m = mass

k = spring constant

Substitute the values into above formula as follows.

T = 2 \pi \sqrt\frac{m}{k}\\= 2 \times 3.14 \times \sqrt\frac{5}{6}\\= 5.73 s

Thus, we can conclude that the period of a spring if it has a mass of 5 kg and a spring constant of 6 N/m is 5.73 sec.

5 0
3 years ago
A SI unit used to measure force, equal to less than one-quarter of a pound, is the what
bulgar [2K]

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1 newton is the force that accelerates a 1 kilogram mass
at the rate of 1 meter per second².

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4 0
3 years ago
Planets are not uniform inside. Normally, they are densest at the center and have decreasing density outward toward the surface.
SSSSS [86.1K]

Answer:

a = 9.94 m/s²

Explanation:

given,

density at center= 1.6 x 10⁴ kg/m³

density at the surface = 2100 Kg/m³

volume mass density as function of distance

\rho(r) = ar^2 - br^3

r is the radius of the spherical shell

dr is the thickness

volume of shell

dV = 4 \pi r^2 dr

mass of shell

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now,

dM = (\rho_0 - br)(4 \pi r^2)dr

integrating both side

M = \int_0^{R} (\rho_0 - br)(4 \pi r^2)dr

M = \dfrac{4\pi}{3}R^3\rho_0 - \pi R^4(\dfrac{\rho_0-\rho}{R})

M = \pi R^3(\dfrac{\rho_0}{3}+\rho)

we know,

a = \dfrac{GM}{R^2}

a = \dfrac{G( \pi R^3(\dfrac{\rho_0}{3}+\rho))}{R^2}

a =\pi RG(\dfrac{\rho_0}{3}+\rho)

a =\pi (6.674\times 10^{-11}\times 6.38 \times 10^6)(\dfrac{1.60\times 10^4}{3}+2.1\times 10^3)

a = 9.94 m/s²

7 0
2 years ago
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