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lawyer [7]
3 years ago
14

Why does magma rise from depth to the surface of the earth?

Physics
2 answers:
Viefleur [7K]3 years ago
6 0

Answer

Magma is less dense compared to the surrounding rock.

the overlying rock creates pressure which forces the magma to be directed upward.

Explanation:

at high temperatures the magma is liquid form with the high energy which causes the formation of bonds and the pressure build up creates the increase  channeling of the liquid.as the temperature decreases the magma moves into the surface

grigory [225]3 years ago
4 0

Explanation:

Any rock will melt once it reaches a high enough temperature. This liquid rock is known as magma when it is beneath the crust of the Earth. If it bubbles to the surface and pushes its way out, it is known as lava. This happens most often in a volcano.

Magma rising from the depth occurs when hot mantle rock rises to shallower depths in the Earth because it is less dense than surrounding rock and because the weight of the overlying rock creates pressure that squeezes magma upward.

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A car initially at rest undergoes uniform acceleration for 6.32 seconds and covers a distance of 120 meters. What is the approxi
Alja [10]
The approximate acceleration of the car would be <span>3.00

</span>How? We have to use the formula to find the velocity.

v = d/t = 120/6.32

v = 19

Then plug the factor into the acceleration formula to find the acceleration:

a = v/t = 19/6.32

a = 3.00

So, the approximate acceleration of the car would be 3.00
4 0
4 years ago
How you do this resistor in circuit question?
lawyer [7]
If Resistors are in series= The equivalent is the sum.

E.g R1 and R2 in series,  R = R1 + R2.

If in Parallel, equivalent is Product/sum.

E.g If R1 and R2 in parallel,  R = (R1*R2)/(R1+R2)

1.)    60 is parallel with 40 and both are then in series with 20.

60//40   = (60*40)/(60+40) = 2400/100 = 24 

Now the 24 is in series with the 20 

R = 24 + 20 = 44 ohms.

2.)    80 is in series with 40 and both are then in parallel with 40.

Solving the series,  R = 80 + 40 =120.

Parallel:   120//40  =     (120*40)/(120+40) =  4800/160 = 30 
Equivalent Resistance = 30 ohms.

3.) 100 is in parallel with 100 and both are then in series with the parallel of 50 and 50.

The 1st parallel  =  (100*100)/(100+100) = 10000/200 = 50

The 2nd parallel  =  (50*50)/(50+50)  = 2500/100   = 25.

Solving the series  = 50 + 25 =75 ohms.

Cheers.
3 0
4 years ago
Sue played four games of golf the modal score was 98 and the mean 100 and the range 10 What were the scores for the games
Lyrx [107]

Answer:

Explanation:

Let the highest and lowest score be a and b respectively .

a - b = 10

a = 10 + b

The numbers in descending order are a , 98 , 98 , b .

mean = 100 , so

4 x 100 = a + 98 + 98 + b = 10 + b  + 98 + 98 + b = 206 + 2b

400 = 206 + 2b

2b = 194

b = 97

a = 107

So the scores were as follows

107 , 98 , 98 , 97

7 0
3 years ago
A body of mass 450g changes it speed from 5ms¹ to 25ms¹. what is the work done by the body?​
Andrej [43]

Answer:

135J

Explanation:

So we know ΔKinetic Energy= ΔWork

Kinetic energy=1/2mv²

So Kf-Ki=ΔK

ΔK=1/2*0.45(25²-5²)=135J

135J=ΔWork

3 0
3 years ago
Uranium-238 has a half-life of 4.5 billion years. Given that scientists estimate Earth's age to be 4.6 billion years, what is th
anyanavicka [17]

Answer:

103.3 %

Explanation:

For a radioactive isotope, the number of radioactive nuclei left (parent nuclei) after a time t, N(t), is

N(t)=N_0 (\frac{1}{2})^{\frac{t}{\tau}}

where

N0 is the initial number of radioactive nuclei

t is the time

\tau is the half-life of the isotope

Here we have

t=4.5 \cdot 10^9 y\\\tau = 4.6\cdot 10^9 y

So we find

\frac{N(t)}{N_0}=(\frac{1}{2})^{\frac{4.5\cdot 10^9}{4.6\cdot 10^9}}=0.508

Which means that the fraction of parent nuclei left after this time is 0.508 (50.8% of the initial value). So the fraction of daugther nuclei at this time is

\frac{N_d}{N_0}=1-0.508=0.492

So the percentage of parent to daughter isotopes is

\frac{N(t)}{N(d)}=\frac{0.508}{0.492}=1.033

Which corresponds to 103.3 %.

5 0
3 years ago
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