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wlad13 [49]
3 years ago
11

How do you transfer kinetic energy to electrical energy using a generator system

Physics
2 answers:
BartSMP [9]3 years ago
4 0

Answer:

A turbine converts the potential and kinetic energy of a moving fluid (liquid or gas) to mechanical energy. In a turbine generator, a moving fluid—such as water, steam, combustion gases, or air—pushes a series of blades mounted on a shaft, which rotates the shaft connected to a generator

Explanation:

A common method of producing electricity is from generators with an electromagnet—a magnet produced by electricity—not a traditional magnet. The generator has a series of insulated coils of wire that form a stationary cylinder. This cylinder surrounds a rotary electromagnetic shaft. When the electromagnetic shaft rotates, it induces a small electric current in each section of the wire coil. Each section of the wire coil becomes a small, separate electric conductor. The small currents of the individual sections combine to form one large current. This current is the electricity that moves through power lines from generators to consumers.

Diagram of an electricity generator - Spinning rotor turning coiled copper wire inside stationary magnets to generate electricity.

Electric generator

Most of U.S. electricity generation is from electric power plants that use a turbine or similar machine to drive electricity generators.

A turbine converts the potential and kinetic energy of a moving fluid (liquid or gas) to mechanical energy. In a turbine generator, a moving fluid—such as water, steam, combustion gases, or air—pushes a series of blades mounted on a shaft, which rotates the shaft connected to a generator. The generator, in turn, converts the mechanical energy to electrical energy based on the relationship between magnetism and electricity.

san4es73 [151]3 years ago
3 0

Answer: so when a turbine converts the K.E and the potential of any moving fluid (more likely liquid or gas) to energy. once the proc is started the turbine generato, the fluid such as water, steam, combus gasses, or air pushes s big series of blades that have mounted on a shaft, which then will rotate the shaft that’s conn to the generator

Explanation: hope this helped plz mark brainest

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Match each word to it's correct meaning.
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Answer:

fluid transfer of heat by the motion of the particles of gas or fluid

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Draw a neat labelled diagram for a particle moving in a circular path with a constant speed. In your diagram show the direction
Naya [18.7K]

Explanation:

Particle moving in a circular path with a constant speed.

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3 years ago
Ngan has a weight of 314.5 N on Mars and a weight 833.0 N on Earth. What is Ngan's mass on Earth?
mr_godi [17]

Ngan's mass on earth is 85kg.

Ngan has a weight on Mars = 14.5 N

Ngan’s weight on Earth = 833.0 N

Ngan’s mass on Earth = ?

<span>Fg,earth = mg(earth)</span>

<span>M = Fg,earth </span><span>/ g(earth)</span>

<span>M = 833.0 N / 9.8 m/s2</span>

<span>M = 85 kg</span>

4 0
3 years ago
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A body which has surface area 5cm² and temperature of 727°C radiates 300J of energy in one minute. Calculate it's emissivity giv
cestrela7 [59]
<h2>Answer: 0.17</h2>

Explanation:

The Stefan-Boltzmann law establishes that a black body (an ideal body that absorbs or emits all the radiation that incides on it) "emits thermal radiation with a total hemispheric emissive power proportional to the fourth power of its temperature":  

P=\sigma A T^{4} (1)  

Where:  

P=300J/min=5J/s=5W is the energy radiated by a blackbody radiator per second, per unit area (in Watts). Knowing 1W=\frac{1Joule}{second}=1\frac{J}{s}

\sigma=5.6703(10)^{-8}\frac{W}{m^{2} K^{4}} is the Stefan-Boltzmann's constant.  

A=5cm^{2}=0.0005m^{2} is the Surface area of the body  

T=727\°C=1000.15K is the effective temperature of the body (its surface absolute temperature) in Kelvin.

However, there is no ideal black body (ideal radiator) although the radiation of stars like our Sun is quite close.  So, in the case of this body, we will use the Stefan-Boltzmann law for real radiator bodies:

P=\sigma A \epsilon T^{4} (2)  

Where \epsilon is the body's emissivity

(the value we want to find)

Isolating \epsilon from (2):

\epsilon=\frac{P}{\sigma A T^{4}} (3)  

Solving:

\epsilon=\frac{5W}{(5.6703(10)^{-8}\frac{W}{m^{2} K^{4}})(0.0005m^{2})(1000.15K)^{4}} (4)  

Finally:

\epsilon=0.17 (5)  This is the body's emissivity

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Easy ! 

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Pluck any string.  Then, slightly twist the tuning peg for that string,
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Twisting the peg only changed the string's tension; the length
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-- If you twisted the peg in the direction that made the string slightly
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-- If you twisted the peg in the direction that made the string slightly
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3 years ago
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