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motikmotik
3 years ago
13

Do you feel that people’s safety is compromised when they live near a nuclear power plant? Why or why not? What sort of informat

ion do you think that someone living near a power plant should try to obtain? Why?
Chemistry
1 answer:
Olegator [25]3 years ago
6 0
So, personally, I think it's not that safe to live right by a nuclear plant because it contains radioactive energy and that is unhealthy to the human body. Living by one a person should also take the precautions that it could have a malfunction and that could cause a fatal accident, an explosion. With that radioactive energy is released and both ruins the area and destroys everything. Well my answer is not that great but I hope this helps. 
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mr_godi [17]

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health issues and physical encounters

4 0
3 years ago
1.) A metal...
Vera_Pavlovna [14]

Answer:

B

Explanation:

Bad conductor of elecricity

5 0
3 years ago
The substances in a chemical reaction that are combined or separated to form new substances are the _______.
katen-ka-za [31]
Reactant/ Reagents and Products
6 0
3 years ago
Read 2 more answers
Calculate the standard heat of reaction for the following methane-generating reaction of methanogenic bacteria: 4CH3NH2(g) + 2H2
PIT_PIT [208]

<u>Answer:</u> The standard heat for the given reaction is -138.82 kJ

<u>Explanation:</u>

Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles.

The equation used to calculate enthalpy change is of a reaction is:

\Delta H^o_{rxn}=\sum [n\times \Delta H_f_{(product)}]-\sum [n\times \Delta H_f_{(reactant)}]

For the given chemical reaction:

4CH_3NH_2(g)+2H_2O(l)\rightarrow 3CH_4(g)+CO_2(g)+4NH_3(g)

The equation for the enthalpy change of the above reaction is:

\Delta H_{rxn}=[(3\times \Delta H_f_{(CH_4(g))})+(1\times \Delta H_f_{(CO_2(g))})+(4\times \Delta H_f_{(NH_3(g))})]-[(4\times \Delta H_f_{(CH_3NH_2(g))})+(2\times \Delta H_f_{(H_2O(l))})]

We are given:

\Delta H_f_{(H_2O(l))}=-285.8kJ/mol\\\Delta H_f_{(NH_3(g))}=-46.1kJ/mol\\\Delta H_f_{(CH_4(g))}=-74.8kJ/mol\\\Delta H_f_{(CO_2(g))}=-393.5kJ/mol\\\Delta H_f_{(CH_3NH_2(g))}=-22.97kJ/mol

Putting values in above equation, we get:

\Delta H_{rxn}=[(3\times (-74.8))+(1\times (-393.5))+(4\times (-46.1))]-[(4\times (-22.97))+(2\times (-285.8))]\\\\\Delta H_{rxn}=-138.82kJ

Hence, the standard heat for the given reaction is -138.82 kJ

3 0
3 years ago
Position (m)
Alex777 [14]

Option C. The object is returning to the start at a constant speed.

<h3>Data points of the Position vs Time graph</h3>

The following data points will be used to determine the motion of the object.

<u>Position               Time</u>

12                          4

10                          6

2                            8

0                           10

From the data above, the position of the object is decreasing towards zero or start point.

Thus, the object is returning to the start at a constant speed.

Learn more about position here: brainly.com/question/2364404

#SPJ1

8 0
2 years ago
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