Qualitative chemical and enzyme tests helped Avery identify DNA as the transforming principle by conducting <span>a series of tests to find out if the transforming principle was DNA or a protein and the result is that </span>no protein was present but that DNA was present. Hope this answers your question.
Answer:
Explanation:
An electron-donating heteroatom substituent at position-2 of a furan promotes regiospecific opening of the 7-oxa bridge of the Diels-Alder cycloadduct with hexafluoro-2-butyne, producing a 4-heterosubstituted 2,3-di(trifluoromethyl)phenol building block in a single step. The phenol and heteroatom substituent are easily transformed to the corresponding iodide or triflate that readily undergoes Heck, Suzuki, and Stille reactions to install a variety of substituents in high yields. This methodology provides a facile and general synthesis of 1,4-disubsituted 2, 3-di(trifluoromethyl)benzenes.
Following is the balanced <span>radioactive decay series:
</span><span>
Particle/radiations generated during the reaction are labeled in bold at end of reaction.
Care must be taken that, atomic number and atomic mass number should be balanced in each of these reactions.
1) 92 238U </span>→ <span> 90 234Th + 2 4He(</span>α particle<span>)
A = </span>90 234Th because alpha particle is emitted along with it. So atomic number of daughter element has to be 92 - 2 = 90. This corresponds to Th. <span>
2) 90 234Th </span>→<span> 91 234Pa + -1 0e (electron)
B = -1 0e i.e electron because after radioactive disintegration atomic number of daughter element (Pa) is +1 as compared to parent element (Th)
3) 91 234Pa </span>→<span> 92 234U + –1 0e (electron)
</span>C = 92 234U because electron is emitted along with it. So atomic number of daughter element has to be 91 - (-1) = 92. This corresponds to U. <span>
4) 92 234U </span>→ 90 230Th + 2 4He (α particle<span>)
</span><span>In this case, 92 234U undergoes nuclear disintegration to generate 90 230Th and alpha particle
5) 90 230Th </span>→<span> 88 226Ra + 2 4He </span>(α particle)
D = 88 226Ra because alpha particle is emitted along with it. So atomic number of daughter element has to be 90 - 2 = 88. This corresponds to Ra.
<span>6) 88 266Ra </span>→ 86 222Rn + 2 4He (α particle)
E = alpha particle because during nuclear disintegration, 88 266Ra is converted into 86 222Rn. Hence, for mass balance we have 88 - 86 = 2. It corresponds to alpha particles.
<span>
7) 86 222Rn </span>→<span> 84 218Po + 2 4He </span>(α particle)
Again, F = alpha particle because during nuclear disintegration, 86 222Rn is converted into 84 218Rn. Hence, for mass balance we have 86 - 84 = 2. It corresponds to alpha particles.
<span>
8) 84 218Po </span>→<span> 82 214Pb + 2 4He </span>(α particle)
G = 82 214Pb because alpha particle is emitted along with it. So atomic number of daughter element has to be 84 - 2 = 82. This corresponds to Pb.
<span>
9) 82 214Pb </span>→<span> 83 214Bi + -1 0e (electron)
H = </span>-1 0e because after radioactive disintegration atomic number of daughter element (Bi) is +1 as compared to parent element (Pb)<span>
10) 83 214Bi </span>→<span> 84 214Po + –1 0e (electron)
I = </span>84 214Po because electron is emitted along with it. So atomic number of daughter element has to be 83 - (-1) = 84. This corresponds to Po.<span>
11) 84 214Po </span>→<span> 82 210Pb + 2 4He </span>(α particle)
J = 82 210Pb because alpha particle is emitted along with it. So atomic number of daughter element has to be 84 - 2 = 82. This corresponds to Pb.
Answer:
0.2M NaOh
Explanation:
there are 0.2 mol of NaOH in 8.0 g. (8.0/40) =0.2. Molarity = mol/L = 0.2M.
<span>The sun and planets formed from a collapsing spinning cloud of gas and dust.</span>
