Answer:
Jeweler B = more accurate
Jeweler A = more precise
Error:
0.008, 0
% error :
0.934% ; 0
Explanation:
Given that:
True mass of nugget = 0.856
Jeweler A: 0.863 g, 0.869 g, 0.859 g
Jeweler B: 0.875 g, 0.834 g, 0.858 g
Official measurement (A) = 0.863 + 0.869 + 0.859 = 2.591 / 3 = 0.864
Official measurement (B) = 0.875 + 0.834 + 0.858 = 2.567 / 3 = 0.8556
Accuracy = closeness of a measurement to the true value
Accuracy = true value - official measurement
Jeweler A's accuracy :
0.856 - 0.864 = - 0.008
Jeweler B's accuracy :
0.856 - 0.856 = 0.00
Therefore, Jeweler B's official measurement is more accurate as it is more close to the true value of the gold nugget.
However, Jeweler A's official measurement is more precise as each Jeweler A's measurement are closer to one another than Jeweler B's measurement which are more spread out.
Error:
Jeweler A's error :
0.864 - 0.856 = 0.008
% error =( error / true value) × 100
% error = (0.008/0.856) × 100% = 0.934%
Jeweler B's error :
0.856 - 0.856 = 0 ( since the official measurement as been rounded to match the decimal representation of the true value)
% error = 0%
Answer:
The answer is Steam is produced when water is heated. The color does not change, a precipice is not formed, and the odor does not change!
Answer:
Carbon dioxide, water, and sunlight
Explanation:
Answer:
There will be formed 3.5 moles of Al2O3 ( 356.9 grams)
Explanation:
Step 1: Data given
Numbers of Al = 7.0 mol
Numbers of mol O2 = O2
Molar mass of Al = 26.98 g/mol
Molar mass of O2 = 32 g/mol
Step 2: The balanced equation
4Al(s) + 3O2(g) → 2Al2O3(s)
Step 3: Calculate limiting reactant
For 4 moles Al we need 3 moles O2 to produce 2 moles Al2O3
Al is the limiting reactant, it will be consumed completely (7 moles).
O2 is in excess. There will react 3/4 * 7 = 5.25 moles
There will remain 9-5.25 = 3.75 moles
Step 4: Calculate moles Al2O3
For 4 moles Al we'll have 2moles Al2O3
For 7.0 moles of Al we'll have 3.5 moles of Al2O3 produced
Step 5: Calculate mass of Al2O3
Mass Al2O3 = moles Al2O3 * molar mass Al2O3
Mass Al2O3 = 3.5 moles* 101.96 g/mol
Mass Al2O3 = 356.9 grams
There will be formed 3.5 moles of Al2O3 ( 356.9 grams)
