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3 years ago

It took 10.40 mL of a NaOH solution to neutralize 0.307 g of KHP. What is the molarity of the NaOH solution

Chemistry

1 answer:

maks197457 [2]3 years ago

5 0

Answer:

0.144 M

Explanation:

First we <u>convert 0.307 g of KHP (potassium hydrogen phthalate, KHC₈H₄O₄) into moles</u>, using its<em> molar mass</em>:

0.307 g ÷ 204.22 g/mol = 0.0015 mol KHP

1 mol of KHP reacts with 1 mol of NaOH, that means that <em>in 10.40 mL of the NaOH solution there were 0.0015 moles of NaOH</em>.

Now we calculate the molarity of the NaOH solution:

10.40 mL / 1000 = 0.0104 L

Molarity = 0.0015 mol / 0.0104 L = 0.144 M

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