Question

It took 10.40 mL of a NaOH solution to neutralize 0.307 g of KHP. What is the molarity of the NaOH solution

Answer 1

Answer:

0.144 M

Explanation:

First we convert 0.307 g of KHP (potassium hydrogen phthalate, KHC₈H₄O₄) into moles, using its molar mass:

• 0.307 g ÷ 204.22 g/mol = 0.0015 mol KHP

1 mol of KHP reacts with 1 mol of NaOH, that means that in 10.40 mL of the NaOH solution there were 0.0015 moles of NaOH.

Now we calculate the molarity of the NaOH solution:

• 10.40 mL / 1000 = 0.0104 L

• Molarity = 0.0015 mol / 0.0104 L = 0.144 M